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Lilit [14]
3 years ago
5

Bernice created a table using her knowledge of charged and uncharged objects. Which statement best explains why the table is inc

orrect?
Charged Object Uncharged Object
Negatively charged attract
Positively charged repel
The negatively charged and uncharged objects do not attract.
A positively charged object attracts an uncharged object.
Both positive and negative charges repel uncharged objects.
An uncharged object neither attracts nor repels charged objects.
Chemistry
2 answers:
Lisa [10]3 years ago
7 0

Answer: Hi

Explanation:

topjm [15]3 years ago
5 0

Answer: d

An uncharged object neither attracts nor repels charged objects

Explanation:

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vekshin1

Typically, the actual yield is lower than the theoretical yield because few reactions complete (i.e., are not 100% efficient) or because not all of the product in a reaction is collected. It is also conceivable for the real yield to exceed the theoretical yield.

What is theoretical yield ?

Theoretical yield is what would be obtained if 100% of the reaction was completed and no product was wasted in any way; however, procedures are not this efficient. Everything is dependent on the experimenter's precision and the reaction. Some reactions are reversible, meaning that less than 100% of the reaction proceeds to completion; some reactions do not go to completion because they require a large amount of energy or additional time, for example. Substances in the reaction may be lost throughout the method or difficult to separate from other sections of the experiment. In chemistry, some degree of inaccuracy is always expected.

To learn more about theoretical yield
brainly.com/question/25996347
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5 0
1 year ago
The pH of an acid solution is 5.82. Calculate the Ka for the monoprotic acid. The initial acid concentration is 0.010 M.
blagie [28]

Answer:

The answer is

<h3>Ka = 2.29 \times  {10}^{ - 14} moldm^{ - 3}</h3>

Explanation:

The Ka of an acid when given the pH and concentration can be found by

<h3>pH =  -  \frac{1}{2}  log(Ka)  -  \frac{1}{2}  log(c)</h3>

where

c is the concentration of the acid

From the question

pH = 5.82

c = 0.010 M

Substitute the values into the above formula and solve for Ka

We have

<h3>5.82 =   - \frac{1}{2}  log(Ka)  -  \frac{1}{2}  log(0.010)</h3><h3 /><h3>-  \frac{1}{2}  log(Ka)  = 5.82 + 1</h3><h3 /><h3>-  \frac{1}{2}  log(Ka)  = 6.82</h3>

Multiply through by - 2

<h3>log(Ka)  =  - 13.64</h3>

Find antilog of both sides

We have the final answer as

<h3>Ka = 2.29 \times  {10}^{ - 14} moldm^{ - 3}</h3>

Hope this helps you

8 0
3 years ago
How many moles is 1200 grams of Mn3(SO4)7?
irga5000 [103]

no.of moles= mass/ Mr

=1200/(54.9*3)+7[32.1+(16*4)]

=1.433

6 0
3 years ago
Read 2 more answers
Please somone help me with a chemistry question brainliest to whoever answers correctly and 20 points
Zina [86]

Answer:

3132 is the answer

Explanation:

3BaCl2 + Al2S3 → 3BaS + 2AlCl3

3 0
3 years ago
Read 2 more answers
What is the value of for this aqueous reaction at 298 K? <br> A+B↽⇀C+D<br> ΔG°=12.86 kJ/mol<br> K=
kogti [31]

Answer:

Kc = 0.5951 (4 sig. figs.)

Explanation:

For A + B ⇄ C + D at standard thermodynamic conditions (298K, 1atm)

ΔG = ΔG° + R·T·lnQ => 0 = ΔG° + R·T·lnKc => ΔG° = - R·T·lnKc

=> lnKc = - ΔG°/R·T

ΔG° = +12.86 Kj/mol

R = 8.314 Kj/mol·K

T = 298K

lnKc = - (+12.86Kj) / (8.314Kj/mol·K)(298K) = - 0.519 mol⁻¹

Kc = e⁻⁰°⁵¹⁹ mol⁻¹ = 0.5957 mol⁻¹ (4 sig. figs.)

5 0
3 years ago
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