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notsponge [240]
2 years ago
10

9. the answer is not 100.0(ect.), plese help me

Chemistry
2 answers:
ArbitrLikvidat [17]2 years ago
5 0
2.56 is the answer !!!!
o-na [289]2 years ago
3 0
What this guy said^^^^^^^
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As
Mars2501 [29]

Explanation:

  1. area of rectangle=l×b
  • 15=5×b
  • b=3cm

2.area of rectangle=l×b

  • 28=l×4
  • l=7cm

3. perimeter of square=4×L

  • 24=4×L
  • L=6cm

4. perimeter of rectangle=2(L+b)

  • 14=2(4+b)
  • 14=8+2b
  • 2b=6
  • b=3cm

hope it helps.

4 0
2 years ago
Read 2 more answers
How does the jet stream influence weather?
LiRa [457]
Jets streams play a key role in determining the weather because they usually separate colder air and warmer air.
4 0
3 years ago
Scientists need special tools to work in the laboratory. These tools are known as___________
inessss [21]
Instruments

The specific type of instruments depends on the type of laboratory that you're working in: some labs for example use electron microscopes, others use mass spectrophotometers, others use multiplex biochemical analyzers, etc. But very broadly, the specialized tools we use in the laboratory are usually referred to as "instruments"
3 0
3 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
You want to test how the mass of a reactant affect the speed of a reaction which of the following is an example of a controlled
emmainna [20.7K]

Answer:A

Explanation:

6 0
3 years ago
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