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Digiron [165]
2 years ago
7

You position two plane mirriors at right angles to each other a light ray strikes one mirrior at an angle of 60 to the normal an

d reflects towards the second mirrior what is the angle of reflection off the second mirrior
Physics
1 answer:
Dafna1 [17]2 years ago
4 0

Answer:

30 degrees

Explanation:

Reflects off of mirror 1  at   60 degrees....this makes it incident to second mirror at 30 degrees ....then angle of reflection equals this angle of incidence = 30 degrees

See atached diagram

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Two objects were lifted by a machine.One object had a mass of 2 kilograms and was lifted at a speed of 2 m/sec.The other had a m
NikAS [45]

Answer:

While lifting two object the machine needs the different momentum for different mass object.

Explanation:

  • Momentum is the quantity of motion contained in an object. Usually it is measured by the product of mass and velocity.
  • Momentum of first mass = 2 kg × 2 m/sec = 4 kg m/sec
  • Momentum of second mass = 4 kg × 3 m/sec = 12 kg m/sec
  • So the machine requires higher mass in motion for second object ( i.e. momentum) than the first one while lifting.
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Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?
Mademuasel [1]
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8 0
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Your friend turns the volume up on their speaker system, so that the sound intensity is 4 times greater than it was beforehand.
erica [24]

Answer:

4

Explanation:

We know that intensity I = P/A where P = power and A = area through which the power passes through.

Now, let the initial intensity of the speaker be I₀ and its initial power be P₀. Since the intensity is increased by a factor of 4, the new intensity be I and new power be P.

So, I = P/A and I₀ = P₀/A

Now, if I = 4I₀,

P/A = 4P₀/A

P = 4P₀

Now, energy E = Pt, where t = time. So, P = E/t and P₀ = E₀/t

Substituting P and P₀ into the equation, we have

P = 4P₀

E/t = 4E₀/t

E = 4E₀

Since the energy is four times the initial energy, the energy output increases by a factor of 4.

4 0
3 years ago
Suppose that two point charges, each with a charge of +3.00 Coulomb are separated by a distance of 3.00 meters. Determine the ma
Sveta_85 [38]

Answer:

9\cdot 10^9 N

Explanation:

The magnitude of the electrical force between the two point charges is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q_1 =q_2 = +3.0 C is the magnitude of each charge

r = 3.00 m is the separation between the two charges

Substituting the numbers into the formula, we find

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(+3 C)^2}{(3.00 m)^2}=9\cdot 10^9 N

3 0
3 years ago
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