3 years ago

I need someone to help me work through this

1 answer:

3 0

The average rate of change of distance over the time interval
3 ≤ t ≤ 6 represents the coin's average velocity over that interval.

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When making a DNA Fingerprint, the job of the restriction enzyme is to..

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3 years ago

Read 2 more answers

Solve for M₂

soldi70 [24.7K]

Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

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3 years ago

A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is

mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate = 150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

$h= \frac{1}{2}at^2$

$h= \frac{1}{2}4.71\times4.96^2$

h= 58.012 m

h≅ 58 m

4 0

3 years ago

If a force of 30N is applied to an object of mass 8kg which is kept on a surface, it achieves an acceleration of 3m/s. What is t

Eduardwww [97]

By Newton's second law, the net force on the object acting parallel to the surface is

∑ F = F[applied] - F[friction] = (8k g) (3 m/s²)

If F[applied] = 30 N, then

30 N - F[friction] = 24 N ⇒ F[friction] = 6 N

so the answer is B.

3 0

2 years ago