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Georgia [21]
2 years ago
13

I need someone to help me work through this

Physics
1 answer:
Sergio039 [100]2 years ago
3 0
The average rate of change of distance over the time interval 
3 ≤ t ≤ 6 represents the coin's average velocity over that interval.
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How can you keep sound out of a room
GREYUIT [131]
To keep<span> noise from entering your space, look for </span>sound<span> blockers</span>
8 0
3 years ago
What is the frequency of a wave if the speed is 24 m/s and the wave is 2 meters
vekshin1
Velocity=frequency(wavelength)
24m/s=f(2m)
24/2=f(2)/2
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4 0
3 years ago
In a nuclear reactor 1 g of mass is converted into energy. How much energy in Joules is produced?
KengaRu [80]

Answer:

3 x 10^5  J

Explanation:

mass of substance, m = 1 g = 0.001 kg

Velocity of light, c = 3 x 10^8 m/s

According to the Einstein mass energy equivalence, the energy associated with the mass is given by

E = m c^2

E = 0.001 x 3 x 10^8

E = 3 x 10^5  J

5 0
3 years ago
What is the momentum of a 200 kg truck travelling at 20 m/s?
geniusboy [140]

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

p=200\times 20\\\\p=4000\ kg-m/s

So, the momentum of the truck is equal to 4000 kg-m/s.

8 0
3 years ago
You push your couch a distance of 3.9 m across the living room floor with a horizontal force of 220.0 n. the force of friction i
Mrac [35]

The general formula to calculate the work is:

W=Fd \cos \theta

where F is the force, d is the displacement of the couch, and \theta is the angle between the direction of the force and the displacement. Let's apply this formula to the different parts of the problem.


(a) Work done by you: in this case, the force applied is parallel to the displacement of the couch, so \theta=0^{\circ} and \cos \theta=1, therefore the work is just equal to the product between the horizontal force you apply to push the couch and the distance the couch has been moved:

W=Fd=(220.0 N)(3.9 m)=858 J


(b) work done by the frictional force: the frictional force has opposite direction to the displacement, therefore \theta=180^{\circ} and \cos \theta=-1. Therefore, we must include a negative sign when we calculate the work done by the frictional force:

W=-Fd=-(144.0 N)(3.9 m)=-561.6 J


(c) The work done by gravity is zero. In fact, gravity (which points downwards) is perpendicular to the displacement of the couch (which is horizontal), therefore \theta=90^{\circ} and \cos \theta=0: this means

W=0.


(d) Work done by the net force:

The net force is the difference between the horizontal force applied by you and the frictional force:

F=220 N-144 N=76 N

And the net force is in the same direction of the displacement, so \theta=0^{\circ} and \cos \theta=1 and the work done is

W=Fd=(76 N)(3.9 m)=296.4 J


4 0
3 years ago
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