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Rama09 [41]
3 years ago
7

A man in a strength competition pulls an 18-wheel truck 3.10 m in 20.5 s. There is a cable that is attached to his body that exe

rts a horizontal force of 756 N. What is the power expended by the man?
Physics
1 answer:
larisa [96]3 years ago
4 0

Answer:

114.32195122 but Round your answer to three significant figures.) is 114

Explanation:

Just took the test

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A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a
hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2

So the magnitude of the total acceleration is

a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2

4 0
4 years ago
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marishachu [46]

6x8 = 48 feet

you can jump 48 feet on the moon

6 0
3 years ago
Carbon-12 and carbon-13 are two different___<br> of carbon.
Agata [3.3K]

Answer: isotopes

Explanation:

7 0
3 years ago
Organize the three states of matter from least kinetic energy to greatest kinetic energy
Yuri [45]

Particle arrangement and movement

⇒ In terms of relative energy, gas particles have the most energy, solid particles have the least energy and liquid particles are somewhere in between. (All compared at the same temperature.)

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8 0
3 years ago
Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile
svetlana [45]
<span>If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field. it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection. There are a number of ways that you could find a horizontally displaced object. You could for example just look.</span>
8 0
3 years ago
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