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3 years ago

14

What is amplitude? I'm pretty dumb lol

2 answers:

Romashka [77]3 years ago

7 0

Amplitude refers to the amount by which something is displaced from the middle of its periodic motion. It can mean the maximum disturbance from the neutral position of a wave. It represents the intensity of a vibration, e.g. the loudness of a sound.

Nady [450]3 years ago

3 0

According to the dictionary, amplitude is: "<span>the maximum extent of a vibration or oscillation, measured from the position of equilibrium."
Hope this helps, and happy studying~!
~{Dunsforhands}</span>

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A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following fun

snow_lady [41]

The correct answer would be 1.375 < t < 3 i hope this helps anyone

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3 years ago

Read 2 more answers

Is (2, 2) a solution of y < 4x-6<br> Help

vesna_86 [32]

Answer:

B) No.

Explanation:

Okay,so,

this is equation is y=mx +b

mx represents the slope

and b represents the y-intercept

in order to figure this out you need to plot the y-intercept first

that makes its (0,-6) because the 6 is negative in the equation

4x is also equal to 4/1 since we dont know what x is

we have to do rise over run for this

you go up 4 spots on the y intercept from -6 because 4 is positive

then you go to the right 1 time because 1 is positive.

this leaves you at (1,-2)

so, (2,2) is NOT a solution

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3 years ago

Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al ca

Nesterboy [21]

Answer:

$0.741\ \text{m/s}^2$

Explanation:

v = Velocidad final = $40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}$

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2$

La aceleración del camión en el primer intervalo de tiempo es $0.741\ \text{m/s}^2$ .

4 0

3 years ago

A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is

neonofarm [45]

Answer:

a) 25.5°(south of east)

b) 119 s

c) 238 m

Explanation:

solution:

we have river speed $v_{r}$ =2 m/s

velocity of motorboat relative to water is $v_{m/r}$ =4.2 m/s

so speed will be:

a) $v_{m}$ = $v_{r}$ + $v_{m/r}$

solving graphically

$v_{m}=\sqrt{v^2_{r}+v^2_{m/r}}$

=4.7 m/s

Ф= $tan^{-1} (\frac{v_{r}}{v_{m/r}} )$

=25.5°(south of east)

b) time to cross the river: t= $\frac{w}{v_{m/r}}$ = $\frac{500}{4.2}$ =119 s

c) d= $v_{r}t$ =(2)(119)=238 m

note :

pic is attached

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3 years ago

What is the length of the X component of the vector plotted below

dlinn [17]

Answer:

5

Explanation:

If you straighten out the line, it touches the 5, which makes the length 5

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3 years ago