Answer:a. Magnetic dipole moment is 0.3412Am²
b. Torque is zero(0)N.m
Explanation: The magnetic dipole moment U is given as the product of the number of turns n times the current I times the area A
That is,
U = n*I*A
But Area A is given as pi*radius² since it is a circular coil
Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is
A = 3.142*(0.05)² =7.86*EXP {-3} m²
Current I is 2 A
Number of turns is 20
So magnetic dipole moment U is
U = 20*2*7.86*EXP {-3}=0.3142A.m²
b. Torque is given as the cross product of the magnetic field B and magnetic dipole moment U
Torque = B x U =B*U*Sine(theta)
But since the magnetic field is directed parallel to the plane of the coil from the question, it means that the angle between them is zero and sine zero is equals 0(zero) if you substitute that into the formula for torque you will find out that your torque would equals zero(0)N.m
Y - yo = Vo*t - g * (t^2) / 2
Vo = - 9.0 m/s
t = 0.50 s
=> y - yo = -9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s)^2 / 2 = - 4.5m - 1.225m = - 5.725 m.
Answer: option c) - 5.7
.Explanation:
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when no net external torque acts on the system then the angular momentum of a system becomes constant. In mechanics and physics, a torque is the spinning counterpart to a force.
The rotating counterpart of linear momentum in physics is called angular momentum. Given that the total angular momentum is conserved, or remains constant in a closed system, it is an important physical quantity. Angular momentum is conserved in both its magnitude and direction. Bicycles, motorcycles, frisbees, rifled bullets, and gyroscopes are all useful objects thanks to the conservation of angular momentum.
The torque is the ratio of the force's magnitude to the angle at which its line of action is perpendicular to the axis of rotation. The cross product of the position vector and the torque, a three-dimensional pseudovector, yields the torque for point particles.
learn more about torque here
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