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3 years ago

An English teacher wants to know the

Mathematics

1 answer:

AfilCa [17]3 years ago

7 0

320

You add all the numbers together then divide by how many numbers there was. In this case all the numbers added to 6405. You divide by 20 because there were 20 numbers. This will get you to 320.25. The closest answer choice would be 320

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Which is an example of Identity Property of Addition?

AURORKA [14]

Answer:

Step-by-step explanation:

because we can not some times change the places in addition so b is the correct answer

8 0

3 years ago

I WILL MARK BRAINLIEST!!!!!!!!!

Lubov Fominskaja [6]

Answer:

It is not

Step-by-step explanation:

It is not because this is an exponential function

y=x^2

1^2=1

2^2=4

3^2=9

4^2=16

7 0

3 years ago

I need help on what to put in the boxes.

Leona [35]

Just divide the y numbers by the x numbers and that's it

7 0

3 years ago

Holly has $125 she spends $35 on gas for her car which model represents how much money holly has left idk if the answer is right

inn [45]

Answer:

The second one would be the answer.

Step-by-step explanation:

If you look at the model, it shows it on 125 going down to 90.

If she has $125 and she spends $35 on gas, you would subtract that from how much money she has.

125 - 35 = 90.

Feel free to let me know if you need more help. :)

5 0

3 years ago

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

4 years ago