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Lostsunrise [7]
3 years ago
5

The volume of 400mL chlorine gas at 400mm Hg is decrease to 200mL at constant tempature. What is the new gas pressure?

Chemistry
1 answer:
storchak [24]3 years ago
3 0
If the volume is cut in half then the pressure is doubles that is boyle's law
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You have a ballon filled with hydrogen gas which keeps it at a constant pressure, regardless the volume. The initial volume of t
abruzzese [7]

Answer:

619°C

Explanation:

Given data:

Initial volume of gas = 736 mL

Initial temperature = 15.0°C

Final volume of gas = 2.28 L

Final temperature = ?

Solution:

Initial volume of gas = 736 mL (736mL× 1L/1000 mL = 0.736 L)

Initial temperature = 15.0°C (15+273 = 288 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 2.28 L × 288 K / 0.736 L

T₂ = 656.6 L.K / 0.736 L

T₂ = 892.2 K

K to °C:

892.2 - 273.15 = 619°C

7 0
2 years ago
HOLMIUM
Sophie [7]

Answer:

1. The graph where x axis and y axis are present is called coordinate.

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8 0
3 years ago
The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of
Drupady [299]
Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
ΔG - changes in Gibbs free energy.
ΔH - changes in enthalpy.
ΔS - changes in entropy.
T is temperature in Kelvins.
When ΔS < 0 (negative entropy change) and ΔH > 0 (endothermic reaction), the process is never spontaneous (ΔG> 0).</span>

5 0
2 years ago
Consider the reaction below. 2K+Br2------&gt;2K+ +2Br-
sergeinik [125]
Answer: only Br2.

Justification.

In  a chemical reaction the element that gains electrons experiments a reduction in its oxidation state, that is why it is said that it is reduced.

So, to know what element is being reduced you need to calculate the oxidation states of the elements involved.

Here I indicate the oxidation states of each element if the reaction putting them inside parenthesis:

Reactants side          Products side

K (0)                           K (1+)
    
Br (0)                          Br(1-)

So, K lost one electron, increasing its oxidation statefrom  0 to 1+, meaning that it is being oxidized.

And, each atom of Br gained one electron, reducing its oxidation state from 0 to 1-, meaning it is being reduced.

Therefore, the answer is that Br2 is the substance being reduced.
3 0
3 years ago
Read 2 more answers
PLZ ANSWER FIRST ONE TO ANSWER GETS BRAINLIEST!!!!!!
Roman55 [17]
The answer is “Heat Conduction”
8 0
3 years ago
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