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4 years ago

What is the correct way to show sodium chloride in aqueous solution? A.NaCl (s) B.NaCl (w) C.NaCl (as) D.NaCl (aq)

2 answers:

5 0

Your answer would be, Sodium Chloride in Aqueous Solution is represented as, Letter choice(D), NaCI(aq), or as HCI + NaOH + H2O(I) + NaCI(aq)

Hope that helps!!!

irina [24]4 years ago

5 0

Answer: D.NaCl (aq)

Explanation: In Sodium chloride

Sodium atom has oxidation number of +1.

Electronic configuration of sodium:

$[Na]=1s^22s^22p^63s^1$

Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.

$[Na^+]=1s^22s^22p^63s^0$

Chlorine atom has oxidation number of -1.

Electronic configuration of sodium:

$[Cl]=1s^22s^22p^63s^23p^5$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]=1s^22s^22p^63s^23p^6$

In sodium chloride the one electron from sodium metal gets transferred to chlorine atom to form ionic compound.

Ionic compounds dissociate to give ions when dissolved in water and thus are written as NaCl (aq).

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4 years ago

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3 years ago

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3 years ago

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3 years ago

A chemist makes up a solution by dissolving 42.0 g of Mg(NO3)2 in enough water to produce a final solution volume of 259 mL. To

Igoryamba

Answer:

The molar mass of Mg(NO₃)₂, 148.3 g/mol.

Explanation:

Step 1: Given data

Mass of Mg(NO₃)₂ (solute): 42.0 g

Volume of solution: 259 mL = 0.259 L

Step 2: Calculate the moles of solute

To calculate the moles of solute, we need to know the molar mass of Mg(NO₃)₂, 148.3 g/mol.

42.0 g × 1 mol/148.3 g = 0.283 mol

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3 years ago