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3 years ago

What is the correct way to show sodium chloride in aqueous solution? A.NaCl (s) B.NaCl (w) C.NaCl (as) D.NaCl (aq)

2 answers:

5 0

Your answer would be, Sodium Chloride in Aqueous Solution is represented as, Letter choice(D), NaCI(aq), or as HCI + NaOH + H2O(I) + NaCI(aq)

Hope that helps!!!

irina [24]3 years ago

5 0

Answer: D.NaCl (aq)

Explanation: In Sodium chloride

Sodium atom has oxidation number of +1.

Electronic configuration of sodium:

$[Na]=1s^22s^22p^63s^1$

Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.

$[Na^+]=1s^22s^22p^63s^0$

Chlorine atom has oxidation number of -1.

Electronic configuration of sodium:

$[Cl]=1s^22s^22p^63s^23p^5$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]=1s^22s^22p^63s^23p^6$

In sodium chloride the one electron from sodium metal gets transferred to chlorine atom to form ionic compound.

Ionic compounds dissociate to give ions when dissolved in water and thus are written as NaCl (aq).

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An example of an ____ reaction is when metals react with oxygen to form metal _____.

Reptile [31]

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4 0

3 years ago

A 251 ml sample of 0.45M HCl is added to 455 mL of distilled water. What is the molarity of the

Oksi-84 [34.3K]

We are given:

251 mL sample of 0.45M HCl added to 455 mL distilled water

Whack a mole! (finding the number of moles):

We know that in order to find molarity, we use the formula:

Molarity = number of moles / Volume (in L)

so, number of moles is:

Number of moles = Molarity * Volume(in L)

now let's plug the values for the HCl solution to find the number of moles

Number of moles = 0.45M * 0.251 L

Number of moles = 0.113 moles

Time to concentrate (finding the final concentration):

Total final volume = 251 mL + 455 mL = 706 mL = 0.706 L

Number of moles of HCl = 0.113 moles

Molarity = Number of moles / Volume (in L)

Molarity = 0.113 / 0.706

Molarity = 0.16 M

___________________________________________________________

BONUS METHOD TIME!!!

We know the relation:

M1 * V1 = M2 * V2

where M1 and M2 are the initial and final molarities and V1 and V2 are initial and final volumes respectively

notice that I didn't mention that the volume has to be in Liters, that's because of the units being concerned with both sides of the equation, say I have the volume in mL and want to convert both these volumes to L, I would divide both sides by 1000, which would NOT change the overall value

Now, plugging values in this equation

(0.45) * (251) = (251 + 455)* (M2)

112.95 = (706)(M2)

M2 = 112.97/706 [dividing both sides by 706]

M2 = 0.16 Molar

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2 years ago

Before a bond breaks in a chemical reaction, what happens

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They have to form a chemical bond in order to brake them down first

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3 years ago

The way it can be determined which type of atom we have is to figure out____are contained within the nucleus of the atom A.elect

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protons and neutrons are in the nucleus electrons surround the atom and i have no idea what positrons are i just know they arent in an atom so your answer is B and C

6 0

3 years ago

Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti

Lina20 [59]

Answer: The volume of stock solution needed is 90 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$