The probability is 3/6 (1/2) as there are 3 prime numbers on a dice (2,3,5) and also 3 odd numbers on a dice (1,3,5)
Using this equation, f(3) = 23.
In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.
f(x) = 2x^2 + 5sqrt(x - 2)
Now place 3 in for each x.
f(3) = 2(3)^2 + 5sqrt(3 - 2)
Now square the 3.
f(3) = 2(9) + 5 sqrt(3 - 2)
Do the subtraction inside of the parenthesis.
f(3) = 2(9) + 5sqrt(1)
Take the square root
f(3) = 2(9) + 5(1)
Multiply.
f(3) = 18 + 5
And add.
f(3) = 23
Answer:
42
Step-by-step explanation:
6 to the second power minius 7 times 3 is 15 then with is cubed it would be 42
Answer:
360,360
Step-by-step explanation:
So we only have 5 spots, but 15 bands to fill those spots.
For the first spot, we can choose from any of the 15 bands, so we have 15 choices.
For the second spot, we can choose from the 14 remaining bands (because we already chose one for the first spot), so we have 14 choices.
For the third spot, by similar reasoning as above, we have 13 choices; for the fourth spot, 12 choices; and for the last spot, we have 11 choices.
We realize that for each of the 15 possible bands in the first spot, we still have 14 possible bands for the second spot, and so on. Thus, we know to multiply instead of add.
Our answer is: 15 * 14 * 13 * 12 * 11 = 360,360
That's the simplest lololol
