So to solve, make an equation (x being the shorter side)
2x+2(7+x)=42
So just solve from here.
2x + 14 + 2x =42
4x=28
x=7
So the shorter side is 7, and the longer side is 14.
Subtract four from both sides. That'll put both numbers without a variable on one side, and the number with the variable is by itself.
Answer:
x = 6
Step-by-step explanation:
Since the triangle is equilateral then sides are congruent.
Equate any 2 sides and solve for x
13x + 5 = 8x + 35 ( subtract 8x from both sides )
5x + 5 = 35 ( subtract 5 from both sides )
5x = 30 ( divide both sides by 5 )
x = 6
JK = (13 × 6) + 5 = 78 + 5 = 83
KL = (17 × 6) - 19 = 102 - 19 = 83
JL = (8 × 6) + 35 = 48 + 35 = 83
ΔJKL is equilateral with side = 83
Answer:
x = 10
Explanation:
Note the following rules before we begin:
2 ln(a) = ln (a²)
ln (a) + ln (b) = ln (ab)
Now, for the given:
ln(20) + ln(5) = 2 ln(x)
ln(20*5) = ln(x²)
ln(100) = ln(x²)
This means that:
100 = x²
Therefore:
either x = 10 .........> acceped
or x = -10 .........> rejected as no negatives are allowed within ln functions
Hope this helps :)
