3 years ago

Number 11 please help !!!

Mathematics

1 answer:

anzhelika [568]3 years ago

4 0

What is the question? are you supposed to solve it

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8n+16.2=1.6 what is n

creativ13 [48]

-1.825. you subtract 16.2 from 1.6. then divide that number by 8

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3 years ago

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Mr. Waugh paid $42.00 for 12 gallons of gasoline. Ms. Peters paid $31.50 for 9 gallons of gasoline. What was theprice per gallon

dmitriy555 [2]

Answer:

$3.50 per pound

Step-by-step explanation:

Divide 42 by 12 or 31.5 by 9 and you get 3.5. In money, that is $3.50

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Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

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3 years ago

Norman bought 5/6 pounds of cookies. He ate 3/5 cookies. What was the weight of the cookies he ate

insens350 [35]

Answer:

Step-by-step explanation:

5/6 pounds he ate 3/5 =0.23

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2 years ago

Image not writing all that.

elena-14-01-66 [18.8K]

Answer:

imagine

Step-by-step explanation:

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