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Crank
3 years ago
11

Round 7E.82 to the nearest whole number

Mathematics
1 answer:
Tasya [4]3 years ago
8 0
It would be either 70.00 or 80.00 I hope I helped u
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The formula for the area of a triangle is
umka21 [38]

Answer:

b = (2A)/h

Step-by-step explanation:

With area formula for triangle:   A = (1/2)*b*h

Solve for b

2*A = 2*(1/2)*b*h

2A = bh

2A / h = b

6 0
3 years ago
Solve for x in the equation 2x^2+3x-7=x^2+5x+39
Shalnov [3]
Hey there, hope I can help!

\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}
2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
x^2-2x-46=0

Lets use the quadratic formula now
\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}
x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}

\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

Multiply the numbers 2 * 1 = 2
\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}

\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \  \left(-2\right)^2=2^2, 2^2 = 4

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \  \sqrt{4+184} \ \textgreater \  \sqrt{188} \ \textgreater \  2 + \sqrt{188}
\frac{2+\sqrt{188}}{2} \ \textgreater \  Prime\;factorize\;188 \ \textgreater \  2^2\cdot \:47 \ \textgreater \  \sqrt{2^2\cdot \:47}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \  \sqrt{47}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \  \sqrt{2^2}=2 \ \textgreater \  2\sqrt{47} \ \textgreater \  \frac{2+2\sqrt{47}}{2}

Factor\;2+2\sqrt{47} \ \textgreater \  Rewrite\;as\;1\cdot \:2+2\sqrt{47}
\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \  2\left(1+\sqrt{47}\right) \ \textgreater \  \frac{2\left(1+\sqrt{47}\right)}{2}

\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \  1+\sqrt{47}

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  2-\sqrt{188} \ \textgreater \  \frac{2-\sqrt{188}}{2}

\sqrt{188} = 2\sqrt{47} \ \textgreater \  \frac{2-2\sqrt{47}}{2}

2-2\sqrt{47} \ \textgreater \  2\left(1-\sqrt{47}\right) \ \textgreater \  \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \  1-\sqrt{47}

Therefore our final solutions are
x=1+\sqrt{47},\:x=1-\sqrt{47}

Hope this helps!
8 0
2 years ago
Read 2 more answers
Solve for x: 3x − 5 = 2x + 6.<br> 1<br> −1<br> 11<br> −11
olga nikolaevna [1]
First you want to get the x's on the same side
3x-5=2x+6
subtract 2x and add 5
x=11

Hope this helps!
5 0
2 years ago
Read 2 more answers
When the population mean and standard deviation are known, what distribution is used for the analysis of the sample?.
Kitty [74]

When the population mean and standard deviation are known, you use the standard normal distribution

<h3>How to determine the distribution?</h3>

There are several probability distributions; these include

  • Normal distribution
  • Poisson distribution
  • Chi square distribution
  • Binomial distribution
  • Etc

Of all these distribution, only the standard normal distribution can be used when the population mean and standard deviation are known,

Note that it is also referred to as the z-distribution

Read more about probability distributions at:

brainly.com/question/24756209

7 0
1 year ago
What is 30=8+4(z-2) step by step?
Stolb23 [73]

30=8+4(z-2)

Distribute 4 through the parentheses

30=8+4z-8

Eliminate the opposites

30=4z

Swap the sides of the equation

4z=30

Divide both sides of the equation by 4

4z÷4=30÷4

Any expression divided by itself equals 1

z=30÷4

or write the division as a fraction

z=30/4

copy the numerator and denominator of the fraction

30=2x3x5

4=2x2

Write the prime factorization of 30

Write the prime factorization of 4

30=2          x3x5

4=2x2

    2

Line up the common factors in both lists

Copy the common factors

Since there is only one common factor, the common factor 2 is also the greatest common factor

30÷2/4÷2

  2

Divide 30 and 4 by the greatest common factor 2

15/4÷2

Divide the numbers in the numerator

15/2

Divide the numbers in the denominator

15/2

The simplified expression is 15/2

That's it. hope it wasn't too hard to understand?

7 0
3 years ago
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