Question

Hi guys please help meee

Answer 1

Answer: 10

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Explanation:

We'll start off converting each mixed number into an improper fraction.

The formula to use is $A \frac{b}{c} = \frac{A*c+b}{c}$

So,

$A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{1}{8} = \frac{2*8+1}{8}\\\\2 \frac{1}{8} = \frac{16+1}{8}\\\\2 \frac{1}{8} = \frac{17}{8}$

And,

$A \frac{b}{c} = \frac{A*c+b}{c}\\\\2 \frac{2}{3} = \frac{2*3+2}{3}\\\\2 \frac{2}{3} = \frac{6+2}{3}\\\\2 \frac{2}{3} = \frac{8}{3}$

So the task of computing $2 \frac{1}{8} \times 2 \frac{2}{3}$ is exactly the same as computing $\frac{17}{8} \times \frac{8}{3}$

Notice how we have an 8 up top and an 8 down below. Those 8's cancel out and we're left with $\frac{17}{3}$. That fraction does not reduce any further.

The last step is to convert that improper fraction result to a mixed number.

$\frac{17}{3} = \frac{15+2}{3}\\\\\frac{17}{3} = \frac{15}{3}+\frac{2}{3}\\\\\frac{17}{3} = 5+\frac{2}{3}\\\\\frac{17}{3} = 5 \frac{2}{3}$

Or you could note that 17/3 leads to 5 remainder 2. The 5 is the whole part and the 2 forms the numerator of the fractional part 2/3.

The value is in $A \frac{b}{c}$ form where

• A = 5
• b = 2
• c = 3

Therefore, A+b+c = 5+2+3 = 10

Answer 2

Answer:

B. 10

Step-by-step explanation:

2 1/8 * 2 2/3

=  8 * 2 + 1 = 17

2 1/8 = 17/8

= 3 * 2 + 2 = 8

2 2/3 = 8/3

17/8 * 8/3

17 * 8 = 136

3 * 8 = 24

136/24 = 17/3 = 5 2/3

5 + 2 + 3 = 10

so I think B. 10 is the answer