The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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It is 96.
triangular part:
1/2 a* g = 1/2 * 8 * 3 = 12 = d
c = √(3²+(8/2)²)=5
square part:2*c + 2*b = 7*2 + 5 * 2 = 24 = e
since you have 2x triangular and 3x squares
2*d+ 3*e = 96
16 : 80
x : 100
Cross multiply.
80× = 100×16
× = 100 × 16 /80
× = 20 grams.
His allowance is 20g of saturated fat.
The answer would be A. -16
