<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>
<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>
To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,
Solve the inequality
Subtract 1000 from both sides
Time cannot be negative
Therefore,
t < 6.61
And the inequality used is: 
Option A is true because the sum of angles in a triangle is 180, so we can rule that one out immediately.
We can solve for x for the other 3 options by setting up this equation:
7x+2 + 4x+7 + 8x = 180 | Simplify
19x + 9 = 180 | Subtract 9
19x = 171 | Divide by 19
x=9
Now we can substitute x into all the values:
<J = 7x+2 = 65
<L = 4x+7 = 43
<K = 8x = 72
Looking at the options again, we can see that A, B, and D are true, leaving C to be false.
The anwser is the first one you put , -4 is below zero
Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so
In this problem we have
substitute
therefore
Polygon q’s area is one fourth of polygon p’s area
