True or False: An equation is balanced by changing subscripts as needed True False
1 answer:
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Answer: 2
Justitification:
1) Property:
![a^{(1/b)} = \sqrt[b]{a}](https://tex.z-dn.net/?f=a%5E%7B%281%2Fb%29%7D%20%3D%20%20%5Csqrt%5Bb%5D%7Ba%7D%20)
Therefore:
![16^{1/4}= \sqrt[4]{16}](https://tex.z-dn.net/?f=16%5E%7B1%2F4%7D%3D%20%20%5Csqrt%5B4%5D%7B16%7D%20)
2) 16 = 2⁴
3) Property
![\sqrt[n]{a^n} =a^{n/n}=a](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Ba%5En%7D%20%3Da%5E%7Bn%2Fn%7D%3Da)
Therefore:
![\sqrt[4]{2^4} =2^{4/4}=2](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B2%5E4%7D%20%3D2%5E%7B4%2F4%7D%3D2)
Justitification:
1) Property:
Therefore:
2) 16 = 2⁴
3) Property
Therefore:
Answer :
The parent and daughter concentrations (in percentages) is, 60 % and 40 % respectively.
The age of rock is
Explanation :
First we have to calculate the parent and daughter concentrations (in percentages).
and,
As we know that, the half-life of uranium-238 = years
Now we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant =
t = time passed by the sample = ?
a = initial amount of the reactant = 3 g
a - x = amount left after decay process = 1.8 g
Now put all the given values in above equation, we get
Therefore, the age of rock is