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ra1l [238]
3 years ago
12

NaCl is a solid at room temperature whereas CCI is a liquid. In terms of the bonding types present, explain this difference.

Chemistry
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

NaCl is a solid at room temperature whereas CCI is a liquid. In terms of the bonding types present, explain this difference.

O NaCl is held together by covalent bonds and CCI, is held together by ionic bonds.

The melting point of covalent bonds is lower

than ionic bonds.

ONaCl is held together by covalent bonds and CCI, is held together by ionic bonds.

The melting point of ionic bonds is lower than

covalent bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds.

The melting point of covalent bonds is lower

than ionic bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds. The melting point of ionic bonds is lower than

covalent bonds.

Answer:



NaCl is a solid at room temperature whereas CCI is a liquid. In terms of the bonding types present, explain this difference.

O NaCl is held together by covalent bonds and CCI, is held together by ionic bonds.

The melting point of covalent bonds is lower

than ionic bonds.

ONaCl is held together by covalent bonds and CCI, is held together by ionic bonds.

The melting point of ionic bonds is lower than

covalent bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds.

The melting point of covalent bonds is lower

than ionic bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds. The melting point of ionic bonds is lower than

covalent bonds.

Answer:



t bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds.

The melting point of covalent bonds is lower

than ionic bonds.

O NaCl is held together by ionic bonds and CCI, is held together by covalent bonds. The melting point of ionic bonds is lower than

covalent bonds.Explanation:



Explanation:



Explanation:

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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

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To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.031M/atm

C_{CO_2} = molar solubility of carbon dioxide gas

p_{CO_2} = partial pressure of carbon dioxide gas = 2.92 atm

Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

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