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asambeis [7]
3 years ago
8

An element consists of two isotopes. One with a mass of 79.95 amu and an abundance of 29.9%. The second isotope has a mass of 81

.95 amu with an abundance of 70.1%. What is the molar mass of this element?
Chemistry
1 answer:
galina1969 [7]3 years ago
5 0

 the molar  mass of the element  is  81.36 g/mol

<u><em>calculation</em></u>

step 1 : multiply  each %abundance  of the isotope  by   its mass  number

that is 79.95 x 29.9 =2391

           81.95 x 70.1  = 5745

Step 2: add them together

2390.5 + 5744.7 =8136

Step 3: divide by 100

= 8136/100 = 81.36  g/mol

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Where is a divergent boundary most likely to be found?
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If the mass of a material is 40 grams and the volume of the material is 9 cm^3, what would the density of the material be?
solniwko [45]
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3 0
3 years ago
How many molecules are in 5.50 grams of AgNO3?
mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

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  • N: 14 g/mole
  • O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

moles=\frac{5.50 grams*1 mole}{169.87 grams}

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}

molecules=1.95*10²²

<u><em>1.95*10²² molecules are in 5.50 grams of AgNO₃</em></u>

3 0
3 years ago
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