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sergey [27]
3 years ago
12

What is the y intercept of a line that has a slope of -3 and passes through point 0.-7?​

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

-7

Step-by-step explanation:

(x,y) --> (0,-7) -7 is the y-intercept

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8 0
3 years ago
Y and x have a proportional relationship, and y = 15 when x = 3. What is the value of x when y = 4?
Ksju [112]
In a proportional relationship, x and y will increase at the same rate. In order to find the value of x when y=4, we first have to find the ratio of x:y. We can do this by creating a fraction. After we know the ratio, simply replace the y value with 4 and solve for x. Here's the math:

y=15 when x=3       given values

y/x = 15/3 = 5          ratio of y to x

y=5x                        equation representing the proportional relationship 

4=5x                        replace y with 4

4/5=x                       divide both sides by 5 to isolate x

Answer: The value of x=4/5 when y=4.

Hope this helps!


6 0
3 years ago
How to use the slope formula to find the slope of a line<br> please help me!!!!!!!
stepan [7]

Answer:

Sweetie, it's easy. Let me explain.

The slope formula is (y2 - y1) (x2 - x1) you find the slope by putting the rise over the run. For example, if the point goes up 2 and right 3 your slope would be (2,3) and let's just say your next coordinate is (4,5) you would take the y, 5, from the second coordinate and subtract it by the y from the first coordinate, 3. So you would have 2 and you do the same with the x values. So your slope would be 3/2. Hope I helped at all.

Step-by-step explanation:


8 0
3 years ago
PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4
Goshia [24]

Answer:

\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

Step-by-step explanation:

y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\

\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

6 0
3 years ago
7/22 rounded to the nearest thousand
saw5 [17]

Answer:

0.318

Step-by-step explanation:

5 0
3 years ago
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