Answer:
- the specific gravity of the block is 0.75
- the specific gravity of the solution is 1.5
Explanation:
Given the data in the question;
first we find the specific gravity of a block SGB
SGB = ( block vol below / total block vol ) × the specific gravity of water
we substitute
SG = ( 1.5 / (1.5 + 0.5 ) ) × 1
SG = ( 1.5 / (1.5 + 0.5 ) ) × 1
SG = (1.5 / 2) × 1
SG = 0.75
Therefore, the specific gravity of the block is 0.75
specific gravity of solution SG
SG = (total block vol / block below ) × SG
we substitute
SG = ( 2 / 1 ) × 0.75
SG = 2 × 0.75
SG = 1.5
Therefore, the specific gravity of the solution is 1.5
Answer:
Explanation:
1. Change object motion - unbalanced force
2. Push or pull - Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces. So if object move it is unbalanced.
3. Have direction - unbalanced force
4. Do not change objects motion - balanced force
5. Net force does not =0 - unbalanced force
6.net force =0 - balanced force
Answer:
ΔH = 14,7kJ/mol
Explanation:
It is possible to make algebraic sum of several chemical process to obtain enthalpy of a determined reaction (Hess's law).
Sublimation of iodine is (Transition from solid to gas):
I₂(s) → I₂(g) ΔH = 60.2kJ/mol
Vaporization of iodine (From liquid to gas):
I₂(l) → I₂(g) ΔH = 45.5kJ/mol
Fusion of iodine (From solid to liquid can be obtained subtracting the sublimation process - Vaporization process:
I₂(s) → I₂(g) ΔH = 60.2kJ/mol
I₂(g) → I₂(l) ΔH = -45.5kJ/mol
I₂(s) → I₂(l) ΔH = 60.2kJ/mol - 45.5kJ/mol
<h3>ΔH = 14,7kJ/mol </h3>
The majority of metals are found in ores.
But a few such as copper, gold, platinum, and silver frequently occur in the free state because they do not readily react with other elements.
Dehyrdration should happen to join two monosaccharide units into a dissacharide. It is used to build up molecules by losing some water moleculse in the process. In a dehydration synthesis reaction between two un-ionized monomers. Hope this answers the question. Have a nice day.