Answer:
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:
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Half life is 15 hours
so 30 hours would be 2 half lives
after 15 hours it would be at 50%
after 15 more hours it would be at 50% of 50%
so .5 x .5 = .25
it would be 25%
Answer:
a. .
b.
c.
Explanation:
Hello,
In this case, considering that the valve is opened, we can use the Boyle's law in order to compute the final pressure of argon by considering its initial pressure and volume and a final volume of 5.0 L:
And the final pressure of helium:
Which actually are the partial pressure of both of them, it means that the total pressure is:
Finally, the mole fraction of each gas is computed by considering the Dalton's law:
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Answer:
3.125 grams.
Explanation:
- It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
- Half-life time is the time needed for the reactants to be in its half concentration.
- If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
- Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
∵ Thulium-167 has a half life of 9.0 days.
∴ The time is needed to calculate the grams are left after (36.0 days) represents (36.0 days / 9.0 days) = 4.0 half-lives.
50.0 grams → (first half life) 25.0 grams → (second half life) 12.5 grams → (third half life) 6.25 grams → (fourth half life) 3.125 grams.
So, the grams are left after 36.0 days = 3.125 grams.
Answer:
<em>1</em><em>.</em><em> </em><em>False</em>
<em>2</em><em>.</em><em> </em><em>True</em>
<em>3</em><em>.</em><em> </em><em>True</em>
<em>4</em><em>.</em><em> </em><em>True</em>