All categories

3 years ago

What is -13 over -10 written as a decimal

Mathematics

1 answer:

Troyanec [42]3 years ago

3 0

Your answer is 1.3, i hope this helped, tell me if you need more help

You might be interested in

Is this a function or no?

zimovet [89]

Function

It is a function

6 0

3 years ago

5x divided by 6 =20 what is the value of x??

natima [27]

Answer:

x = 24

Step-by-step explanation:

5x = 120

x = 120/5

x = 24

3 0

4 years ago

Read 2 more answers

Consider the following function. F(x)=3/2+4 Using the given function, plot all the ordered pairs for the values in the domain be

Butoxors [25]

I can't edit pictures for you so as a result I can't answer it. But label those numbers on the x line and that will be your answer. And OMG your laptop is torn up I tell you TORN.

8 0

4 years ago

Assume that lines that appear to be tangent are tangent. O is the center of the circle. Find the value of x. (Figures are not dr

zimovet [89]

x is 68 as the angles O and x must total 180°

4 0

3 years ago

A random sample of 21 observations is used to estimate the population mean. The sample mean and the sample standard deviation ar

stepladder [879]

Answer:

a. CI=[128.79,146.41]

b. CI=[122.81,152.39]

c. As the confidence level increases, the interval becomes wider.

Step-by-step explanation:

a. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula;

$\bar X\pm \ z\frac{s}{\sqrt{n}},$

where:

$s$ is the sample standard deviation
$z$ is the s value of the desired confidence interval

we then calculate our confidence interval as:

$\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.05/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm1.960\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm8.8108\\\\\\=[128.789,146.411]$

Hence, the 95% confidence interval is between 128.79 and 146.41

b. -Given the sample mean is 137.6 and the standard deviation is 20.60.

-The confidence intervals can be constructed using the formula in a above;

$\bar X\pm z\frac{s}{\sqrt{n}}\\\\=137.60\pm z_{0.01/2}\times\frac{20.60}{\sqrt{21}}\\\\=137.60\pm3.291\times \frac{20.60}{\sqrt{21}}\\\\=137.60\pm 14.7940\\\\\\=[122.806,152.394]$

Hence, the variable's 99% confidence interval is between 122.81 and 152.39

c. -Increasing the confidence has an increasing effect on the margin of error.

-Since, the sample size is particularly small, a wider confidence interval is necessary to increase the margin of error.

-The 99% Confidence interval is the most appropriate to use in such a case.

7 0

4 years ago