This triangle is obtuse( as it's one angle is greater than 90°) as well as isosceles (as it's two sides are equal).
The answer is y= 3/4x - 4.
Step-by-step explanation:
9/8 × (-7/3) =
9 × -7 = -63
8 × 3 = 24
-63/24 simplify
-21/8
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
The answer would be C. because you have to multiply all of the numbers and then divide by the 90 degree angle.