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astra-53 [7]
4 years ago
9

A person is walking on a treadmill. The treadmill is moving backwards at a speed of 3.0 m/s. The person is moving forward relati

ve to the treadmill at 2.5 m/s. What is the person’s velocity relative to the ground?
Physics
1 answer:
Serga [27]4 years ago
4 0

Answer:

V = - 0.5[m/s]

Explanation:

To solve this problem we have to analyze it by means of relative speeds, we have a treadmill that moves at a speed of -3 [m/s], (the negative sign means that it moves in a sense opposite to that of the person). The person moves at a speed of 2.5 [m/s]

Therefore we have from the perspective of a person placed outside

- 3 + 2.5 = - 0.5 [m/s]

Note: This would physically look like the person retreating as he or she walks forward, should increase his or her speed to 3 [m/s] to balance the speed of the band and not get out of it.

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4 years ago
Two balloons (m = 0.021 kg) are separated by a distance of d = 16 m. They are released from rest and observed to have an instant
evablogger [386]

(a) 2.56\cdot 10^{-5} C

According to Newton's second law, the force experienced by each balloon is given by:

F = ma

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Substituting, we found:

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The electrostatic force between the two balloons can be also written as

F=k\frac{Q^2}{r^2}

where

k is the Coulomb's constant

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Since we know the value of F, we can find Q, the magnitude of the charge on each balloon:

Q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(0.0231)(16)^2}{9\cdot 10^9}}=2.56\cdot 10^{-5} C

(b) 1.6\cdot 10^{14} electrons

The magnitude of the charge of one electron is

e=1.6\cdot 10^{-19}C

While the magnitude of the charge on one balloon is

Q=2.56\cdot 10^{-5} C

This charge can be written as

Q=Ne

where N is the number of electrons that are responsible for this charge. Solving for N, we find:

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