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4 years ago

Can someone help explain why hitting/catching a baseball are examples of elastic/inelastic collisions?

2 answers:

6 0

These are all examples of inelastic collisions.
Inelastic collisions are collisions in which energy (kinetic) is lost. All contact collisions are inelastic.

guapka [62]4 years ago

4 0

<span>Elastic collision is a collision where the colliding objects bounce back without undergoing any deformation or heat generation. Inelastic collision is a collision where the colliding objects are distorted and heat is generated.

I hope my answer has come to your help. God bless and have a nice day ahead!
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Does the image above correctly illustrate how the coriolis effect impacts global winds?

Sedbober [7]

Yes the winds are moving in a straight line

6 0

3 years ago

Sherlock Holmes examines a clue by holding his magnifying glass (with

Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

$\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm$

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

$M=-\frac{q}{p}=-\frac{-30}{10}=3$

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

8 0

4 years ago

A 1.35 ×103 kg car rounds a circular turn of radius 11.9 m. The acceleration of gravity is 9.81 m/s 2 . If the road is flat and

mihalych1998 [28]

Answer:

velocity = 8.84 m/s

Explanation:

given data

radius r = 11.9 m

acceleration of gravity g = 9.81 m/s²

static friction μ = 0.67

to find out

how fast can the car go without skidding

solution

we get here velocity that is car go without skidding is express as

force = $\frac{mv^2}{r}$

force = μ × mg

μ × mg = $\frac{mv^2}{r}$

v² = μ × r × g

v = $\sqrt{\mu *r*g}$ ..................1

v = $\sqrt{0.67 *11.9*9.81}$

v = 8.84 m/s

velocity = 8.84 m/s

3 0

3 years ago

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sladkih [1.3K]

It's C, with the 2/7/4/6 in front of each reactant and product.

4 0

4 years ago

What type of energy is cracking an egg

Alex17521 [72]

It is Kinetic energy

6 0

3 years ago