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3 years ago

Helppppp with this. What do I have to do?

Mathematics

1 answer:

vaieri [72.5K]3 years ago

5 0

You need to use the grids to draw rectangles which meet the requirements to help you put the answers in on the right.

1) Short side of 7 and long side of 9.

2) Short side of 9 and long side of 10.

3) Short side of 3 and long side of 8.

4) Short side of 4 and long side of 9.

5) Short side of 3 and long side of 5.

6) Short side of 6 and long side of 8.

7) Short side of 1 and long side of 2

8) Both sides 10 (this is technically a square).

9) Short side of 6 and long side of 9.

10) Short side of 7 and long side of 8.

11) Short side of 2 and long side of 3.

12) Short side of 6 and long side of 9.

You can draw these a few different ways to still get a correct result, so above are just one way of doing it.

You might be interested in

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago

Given x = wavelength and y = frequency are inversely related, solve for the constant for the given type of

Natasha_Volkova [10]

Answer:

given

x = k 1/ y

k = x y

= 300,000 × 40

= 12,000,000

4 0

3 years ago

Read 2 more answers

Click on the photo to see it.

Lera25 [3.4K]

B is the midpoint

$\\ \sf\longmapsto AB=\dfrac{1}{2}AC$

$\\ \sf\longmapsto 7x-3=\dfrac{5}{2}$

$\\ \sf\longmapsto 5=2(7x-3)$

$\\ \sf\longmapsto 5=14x-6$

$\\ \sf\longmapsto 14x=6+5$

$\\ \sf\longmapsto 14x=11$

$\\ \sf\longmapsto x=\dfrac{11}{14}$

$\\ \sf\longmapsto x=7.8$

6 0

3 years ago

Read 2 more answers

What is 12 3/4 - 11 7/8?

Sergeu [11.5K]

11.9 would be the correct answer I believe

3 0

3 years ago

Determine whether the point is on the graph of the equation 2x+3y=8.<br> (1,2)

geniusboy [140]

The point $(1,2)$ is on the graph of the equation.

Explanation:

The equation is $2x+3y=8$

We need to determine the point $(1,2)$ is on the graph.

To determine the point $(1,2)$ is on the graph, we need to substitute the point in the equation and find whether the LHS is equal to RHS.

Thus, substituting the point $(1,2)$ in the equation $2x+3y=8$ , we get,

$2(1)+3(2)=8$

Multiplying the terms within the bracket, we have,

$2+6=8$

Adding the LHS, we have,

$8=8$

Thus, both sides of the equation are equal.

Hence, the point $(1,2)$ is on the graph of the equation $2x+3y=8$

3 0

3 years ago