I think that the best answer here would be that A = 40 degrees.
The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.
Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.
After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.
Do you remember this for a right triangle ? ==> A² + B² = C²
(500H)² + (1200H)² = (650)²
250,000H² + 1,440,000H² = 422,500
1,690,000 H² = 422,500
H² = (422,500) / (1,690,000) = 0.25
H = √0.25 = 1/2 hour = 30 minutes
Answer:
22.35 m/s
Step-by-step explanation:
The distance is always a positive unit, so distance traveled (d) = 15 miles
Time (t) = 0.3 hours
Time (t) = 0.3 * 60 = 18 minutes
(1 hour = 60 minutes)
Velocity (v) = ?
The formula of distance is: d = v*t
=> v = d/t = 15/18 = 0.83 miles/minute
we can also calculate velocity is meter/sec, for that
1 minute = 60 sec
=> 18 mins = 18*60 = 1080 sec
1 mile = 1609.34 meters
=> 15 miles = 15 * 1609.34 = 24,140 m
hence,
v = 24,140/1080 = 22.35 m/s
Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
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<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.
Francisco's wrapping paper measurements
13 2/3×2=27 1/3
17×2=34
Monica's wrapping paper measurements
basically Monica's measurements are 2× more than Francisco's, so if 2 of the sides equal 34 inches each the other 2 sides are 27 1/3 each
