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Fiesta28 [93]
3 years ago
13

What is the sixth term of the sequence an=-3•2n+1a6=

Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

a_6=-384

Step-by-step explanation:

The n^{th} term of the sequence is given as a_n=-3\cdot 2^{n+1}.

To find the sixth term, which is denoted by a_6, we substitute n=6 into the given rule.

This will give us:

a_6=-3\cdot 2^{6+1}

Simplify the exponent to get:

a_6=-3\cdot 2^{7}

We simplify further to get:

a_6=-3\cdot 128

This simplifies to

a_6=-384

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
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8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
3 years ago
You wish to package a spherical globe inside a cubical box . The diameter of the globe is 30 centimeters . How much empty space
Aneli [31]

Answer:

<h2>The empty inside the box is 12,870 cubic centimeters, approximately.</h2>

Step-by-step explanation:

Givens

  • The diameter of the globe (sphere) is 30 centimeters,
  • The box must has dimensions 30x30.

We need to find each volume to subtract them.

V_{box}=(30cm)^{3}=  27,000 \ cm^{3}

V_{sphere}=\frac{4}{3} \pi (15cm)^{3} \approx 14,130 \cm^{3}

The difference betweem the box and the sphere is

\Delta V=27,000 - 14,130 = 12,870 \ cm^{3}

Therefore, the empty inside the box is 12,870 cubic centimeters, approximately.

5 0
2 years ago
Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n
Temka [501]

Answer:

\frac{1}{2}

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= \frac{3}{8} of x

Total number of newspapers delivered in first hour= \frac{3}{8}x

Number of newspapers left= x-\frac{3x}{8}

Number of newspapers left=\frac{8x-3x}{8}

Number of newspapers left=\frac{5x}{8}

Number of newspapers delivered in second hour=4/5 of\frac{5x}{8}

Number of newspapers delivered in second hour=\frac{x}{2}

Fraction of newspapers delivered in second hour is=\frac{1}{2}

Hence, the correct answer is \frac{1}{2}

8 0
3 years ago
AEFG is located at E (0,0), F (-7, 4), and G (0,8). Which statement correctly classifies AEFG?
viva [34]

Answer:

ΔEFG is an isosceles triangle

Step-by-step explanation:

8 0
3 years ago
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