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vlabodo [156]
3 years ago
5

What is the square root of 98673

Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0

the square root of 98673 is 314.122587536

Elina [12.6K]3 years ago
4 0
The square root of 98673 cannot be reduced, since it's already in its simplest form, so the answer would be;

√98673 = 314.122587536
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6) Find the distance between -8 and 10.
ivolga24 [154]
The distance is 18 units and the equation would be (-8 - 10)
8 0
2 years ago
Translate the algebraic expression in written language: 9 - x²​
Assoli18 [71]

Answer:

nine minus x square

8 0
2 years ago
Evaluate (18)^2-(15)^2<br> Please show working.
dexar [7]

Answer:

99

Step-by-step explanation:

You can solve it by Squaring/multiply 18 by itself and 15 by itself then subtract them both:

(18 × 18) - (15 × 15)

324 - 225

99

You could also do difference of two squares:

(x² - y²)

= (x + y) (x - y)

= (18 + 15) (18 - 15)

= (33) (3)

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8 0
2 years ago
Read 2 more answers
Isabella is comparing the values below. Which list shows the values in descending order? 7.42, 7 79%, V48
Afina-wow [57]

Answer:

778%, 7.42, and V48

Step-by-step explanation:

I think that is right

8 0
3 years ago
A marketing research company desires to know the mean consumption of milk per week among people over age 32. A sample of 440 peo
Softa [21]

Answer:

The 98% confidence interval for the mean consumption of milk among people over age 32 is between 3.3 and 3.5 liters.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.8}{\sqrt{440}} = 0.1

The lower end of the interval is the sample mean subtracted by M. So it is 3.4 - 0.1 = 3.3 liters

The upper end of the interval is the sample mean added to M. So it is 3.4 + 0.1 = 3.5 liters

The 98% confidence interval for the mean consumption of milk among people over age 32 is between 3.3 and 3.5 liters.

7 0
2 years ago
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