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vesna_86 [32]
4 years ago
15

makayla wanted to buy cookies for the class the cookies are in 1 package? how many cookies are in 10 packages how many cookies i

n 100 packages
Mathematics
1 answer:
denpristay [2]4 years ago
8 0

Answer:

you didn't put how many cookie are in one package

Step-by-step explanation:

sorry

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Ok im super confused bc like it ask me put i dont know what to put.............pls help me
Ilya [14]

Answer:

u drag the green dot thing over to the coordinate (6,8)

Step-by-step explanation:

i put a black dot where i think ur supposed to drag the green dot to

3 0
3 years ago
If 2x = 5, 3y = 4, and 4z = 3, what is the value of 24xyz ?
NISA [10]
2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)

implement: 24x2.5x1.3•x0.75

hope i answered right
3 0
4 years ago
Select the statement that is FALSE. The range is never greater than the greatest value of a data set. The interquartile range is
Nata [24]

Answer:

The interquartile range is the difference between the highest and lowest values in the middle of a data set.

Step-by-step explanation:

The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.

The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.

The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.

6 0
3 years ago
Packaging By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting fl
Vikki [24]

Answer:

Height: 3/2 inches

Length:  12 inches

Width: 4 inches

Step-by-step explanation:

Let x is the side length of the square

The height of the box by cutting squares off :x

  • The new length of the cardboard = 15 -2x (because we cut from 4 corners)
  • The new width of the cardboard = 7 -2x (because we cut from 4 corners)

The new volume of it is:

V = (15 -2x) (7 -2x) x

<=> V = 4x^3 -44x^2 +105x

To maximum volume, we use the first derivative of the volume

\dfrac{dV}{dx} = 0

<=> 12x^2-88x+105=0

<=> \left(2x-3\right)\left(6x-35\right) = 0

<=> 2x -3 = 0 or 6x -35 = 0

<=> x = 3/2 or x = 35/6

To determine which value of x gives a maximum, we evaluate

\dfrac{d^2V}{dx^2} = 24x -88

  • If  x = 3/2, we have:

\dfrac{d^2V}{dx^2}= 24(3/2) -88  = -52

  • If x = 35/6, we have:

\dfrac{d^2V}{dx^2} = 24(35/6) -88 = 52

We choose x = 3/2 to have the maximum volume because the value of x that gives a negative value is maximum.

So the dimensions (in inches) of the box is:

Height: 3/2 inches

Length: 15-2(3/2) = 12 inches

Width: 7 - 2(3/2) = 4 inches

5 0
3 years ago
What is the benchmark of 6/10
IceJOKER [234]
First split your model into 10 equal sections then you shade/color in 6 of them.
There it goes that is 6/10 bench mark!
~JZ
Hope it helps
3 0
3 years ago
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