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3 years ago

15

makayla wanted to buy cookies for the class the cookies are in 1 package? how many cookies are in 10 packages how many cookies i

n 100 packages

1 answer:

denpristay [2]3 years ago

8 0

Answer:

you didn't put how many cookie are in one package

Step-by-step explanation:

sorry

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What is (f - g)(x)?<br>f(x) = 5x<br>g(x) = 3x2 - 8x

erma4kov [3.2K]

Answer:

$(5x)-(3x^2-8x)=-3x^2+13x$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)$

Using this, we can subtract and find the answer.

$(5x)-(3x^2-8x)=-3x^2+13x$

6 0

2 years ago

Which of the following statements is TRUE about the midline of a trapezoid?

Y_Kistochka [10]

Answer:

C will be the rightful answer

3 0

1 year ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

2 years ago

Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord

Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.

5 0

2 years ago

What does the fact that the expressions are equivalent mean?

NNADVOKAT [17]

Answer:

The fact that the expressions are equivalent means that for any value of the variables, the two expressions have the same solution.

Step-by-step explanation:

3 0

2 years ago