As per the question, the mass of the nitrogen gas m = 22.25 gram.
The latent heat of vaporization of nitrogen = 199.0 j/g
As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.
Hence, the heat released by nitrogen gas Q = ml = 22.25 × 199.0 J = 4427.75 J.
Hence, the amount of heat released will be 4427.75 J.
<h3>How can you figure out how much heat is in each gram?</h3>
The formula: can be utilized to determine energy. Q = mc ∆T. In the equation, Q stands for energy expressed in joules or calories, m for mass expressed in grams, c for specific heat, and T for temperature change, which is the difference between the final temperature and the initial temperature. Water has a specific heat of 1 calorie/gram °C.
Learn more about energy here:
brainly.com/question/1932868
#SPJ4
Answer:
3
Explanation:
The velocity is basically the speed + the direction of an object put into one quantity, <em><u>velocity</u></em>.
hope this helps, if not see me in the comments...
HOPE THIS HELPS BRAINLIEST PLZZ
Answer:
Molarity is a unit that measures how much moles of solute dissolved in a liter of solvent. Molarity expressed using capital M while molarity, a different unit, expressed using lower case m.
We want to make 0.005 M solution which means we need 0.005 moles of KmnO4 per liter of water. First, we have to calculate how many grams of KMnO4 we need for the solution.
We want to make 250ml solution, so the number of moles of KMnO4 we need will be: 0.005 mol/liter *(250 ml * 1liter/1000ml)= 0.005 mol/liter * 1/4 liter = 0.00125 moles
The molecular mass of KMnO4 is 158g/mol, so the mass of KMnO4 we need will be: 0.00125 moles * 158g/mol= 0.1975 grams
We know that we need 0.1975 g of KMnO4, now we weigh them and put it inside a dish. After that, we prepare Erlenmeyer or a volumetric flask filled with water half of the volume needed(125ml). Pour the weighted solute into the flask, stir until all solute dissolved.
Then we add water to the container slowly until its volume reaches the 250ml mark.
6.022*10^23 is the number
