Answer:
Mass of chlorine = 47.22 g
Explanation:
Given data:
Mass of sodium = 30.5 g
Mass of chlorine= ?
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
Number of moles of Na:
Number of moles = mass/molar mass
Number of moles = 30.5g/ 23 g/mol
Number of moles = 1.33 mol
Now we will compare the moles of Cl
₂ with Na from balance chemical equation.
Na : Cl
₂
2 : 1
1.33 : 1/2×1.33 = 0.665 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.665 mol × 71 g/mol
Mass = 47.22 g
Liquid because it is changing to that <span />
Answer:
a) S = 0.0152 mol/L
b) S' = 4.734 g/L
Explanation:
S 2S S...............in the equilibrium
- Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]
a) molar solubility:
⇒ Ksp = ( 2S) ² * S = 1.4 E-5
⇒ 4S² * S = 1.4 E-5
⇒ S = ∛ ( 1.4 E-5 / 4 )
⇒ S = 0.0152 mol/L
b) solubility ( S' ) in grams per liter:
∴ Mw Ag2SO4 = 311.799 g/mol
⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )
⇒ S' = 4.734 g/L
Answer:
0.0451 mol FeCl₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
5.72 g FeCl₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Fe - 55.85 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of FeCl₂ - 55.85 + 2(35.45) = 126.75 g/mol
<u>Step 3: Convert</u>
<u />
= 0.045128 mol FeCl₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.045128 mol FeCl₂ ≈ 0.0451 mol FeCl₂
