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nirvana33 [79]
2 years ago
8

Which buffer can be suitable to prepare a solution that needs to be buffered at pH 4? Explain your

Chemistry
1 answer:
Tcecarenko [31]2 years ago
7 0

.

Which buffer can be suitable to prepare a solution that needs to be buffered at pH 4? Explain your

choice.

A. Formic acid/Formiate buffer

<u>B. Carbonic acid/Bicarbonate buffer</u>

C. Ammonia/Ammonium buffer

D. Any buffer will work.

E. None of the buffers will be suitable.

34 Which of the following will form a buffer when mixed together? Explain <u>a weak acid/base and its conjugate base/acid in the form of salt</u>

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Frayer model for matter
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A model showing that gases are made from the matter of particles that are too small to see and are moving freely around in space can explain many observations.
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3 years ago
Hi :) , if the density of an object is the same as water , will the object float or sink?
Klio2033 [76]

Answer:

it will float if the object is 1g/cm^3(water 's density ) because it is less dense

6 0
3 years ago
In the animation, you can see that the electrons occupy different orbitals according to the energy level of each orbital. A sing
lara31 [8.8K]

B) The He atom has two electrons that have parallel spin in its 1s orbital.

C) Electrons generally occupy the lowest energy orbital first.

D) The arrangement of the orbitals is the same in a multielectron atom and a single-electron atom

E) The C atom has two unpaired electrons.

Explanation:

In writing sublevel notations certain rules are followed:

  • The maximum number of electrons in the orbitals of sublevels are:

             two for s-sublevel with one orbital

             six for p-sublevel with three orbitals

             ten for d-sublevel with five orbitals

             fourteen for f-sublevel with seven orbitals

  • Aufbau's principle states that sublevels with lower energies are filled before those with higher energies.

                    1s 2s 2p 3s 3p 4s 3d 4p 5s    increasing order of filling

  • Pauli exclusion principle states that no two electrons can have the same set of the four quantum numbers i.e electrons in the same orbital cannot spin in the same direction.
  • Hund's rule states that electrons go into degenerate orbitals singly first before pairing up.

Based on these principles and the animation, the following options are correct:

B) The He atom has two electrons that have parallel spin in its 1s orbital.

Helium has two electrons in the 1s orbital. From Pauli's exclusion principle, we see that the two electrons cannot spin in the same way. Therefore, they have parallel spin

C) Electrons generally occupy the lowest energy orbital first.

From Aufbau's principle, electrons go into orbitals with lower energies first before those with higher energies.

D) The arrangement of the orbitals is the same in a multi-electron atom and a single-electron atom

                  1s 2s 2p 3s 3p 4s 3d 4p 5s

Orbitals are arranged in the order of their energies from the lowest to the highest.

E) The C atom has two unpaired electrons.

Configuration for carbon atom is shown below:

                            1s² 2s² 2p²

Learn more:

Orbitals brainly.com/question/1832385

#learnwithBrainly

8 0
3 years ago
Read 2 more answers
Methane is approximately 23 times more powerful than carbon dioxide as a greenhouse gas. Which are significant sources of methan
ratelena [41]

Answer:

anthropogenic sources like landfills, agricultural activities,coal mining and combustion and some sources are natural ones

5 0
3 years ago
You have 26.7 mL of 0.061 mol/L aqueous potassium hydroxide (KOH(aq)) in a conical flask. In a burette
Natasha2012 [34]

Answer:

9.47 mL

Explanation:

The reaction that takes place is:

  • 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O

First we <u>calculate how many KOH moles reacted</u>, using <em>the given concentration and volume of KOH solution</em>:

  • 0.061 mol/L = 0.061 mmol/mL
  • 0.061 mmol/mL * 26.7 mL = 1.6287 mmol KOH

Then we <u>convert KOH moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:

  • 1.6287 mmol KOH * \frac{1mmolH_2SO_4}{2mmolKOH} = 0.8144 mmol H₂SO₄

Finally we <u>calculate the required volume of the H₂SO₄ solution</u>, using<em> the number of moles and given concentration</em>:

  • 0.8144 mmol ÷ 0.086 mmol/mL = 9.47 mL
5 0
3 years ago
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