Answer:
The magnetic field strength due to current flowing in the wire is9.322 x 10⁻⁶ T.
Explanation:
Given;
electric current, I = 21.3 A
distance of the magnetic field from the wire, R = 45.7 cm = 0.457 m
The strength of the resulting magnetic field at the given distance is calculated as;

Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A

Therefore, the magnetic field strength due to current flowing in the wire is 9.322 x 10⁻⁶ T.
" 30% " means " 0.30 "
30% ÷ 75 means (0.30 / 75) = <em>0.004</em>
Answer:
(a) hypermetropia
(b) convex lens
(c) 133.33 cm
(d) - 21.05 cm
Explanation:
(a) As she is old age, so she is suffering from hypermetropia.
(b) It is the defect due to which a person is not able to see the nearby objects clearly, so it is cured by convex lens of suitable focal length.
(c) Power, P = + 0.75 D
Focal length is the reciprocal of power of lens.
f = 1/ P = 1/0.75
f = 133.33 cm
(d) v = -25 cm, f = 133.3 cm
use lens equation



u = - 21.05 cm
I recently received the following question regarding EMP effects: “What will happen to vehicles with electronic ignitions, a Chevy with an ignition module, but they are not hooked to a battery, with no path for electricity to follow, can it do damage? There may not be power on the grid, but what about a generator? Can a drill that was not plugged in still be able to run?”
The short answer is, maybe.
0.022 has 2 digits because you would count from the left starting with the first nonzero number