Fertilizers usually contain two elements from Group 5A, which are

If the formation of a neutron star leads to a supernova explosion, explain why only three of the hundreds of known pulsars are f

Mandarinka [93]

Explanation:

neutron stars have diameters of about 20km and they are denser than the earth. A rotating neutron star pulsating electromagnetic beam is a named a pulsars but not all neutron stars are pulsars.

Only three of hundreds of known pulsar are found in supernova remnants because as neutron stars gets older, they lose energy and starts to decrease their rotational speeds and the neutron star could not radiate particles and energy for long as a pulsar does. there are less existing pulsars compared to supernova explosion rate because the life time of pulsars is obout 10×10^6 years after the neutron can no longer spin at high speeds to produce beams of particles and energy, almost all the pulsars are older and spin slow to produce light of visible wavelength or X-ray wavelengths and we only get a pulse of radiation from a neutron star as a pulsar as the beam sweeps over earth.

8 0

4 years ago

Two wires, both with current out of the page, are next to one another. The wire on the left has a current of 1 A and the wire on

Soloha48 [4]

Answer:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

Explanation:

To know what is the answer you first take into account the magnetic field generated by each current, for a distance of d:

$B_1=\frac{\mu_oI_1}{2\pi d}=\frac{\mu_o}{2\pi d}(1A)\\\\B_2=\frac{\mu_oI_2}{2\pi d}=\frac{\mu_o}{2\pi d}(2A)=2B_1\\\\$

Next, you use the formula for the magnetic force produced by the wires:

$\vec{F_B}=I\vec{L}\ X \vec{B}$

if the direction of the L vector is in +k direction, the first wire produced a magnetic field with direction +y, that is, +j and the second wire produced magnetic field with direction -y, that is, -j (this because the direction of the magnetic field is obtained by suing the right hand rule). Hence, the direction of the magnetic force on each wire, produced by the other one is:

$\vec{F_{B1}}=I_1L\hat{k}\ X\ B_2(-\hat{j})=I_1LB_2\hat{i}=(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}\\\\\vec{F_{B2}}=I_2L\hat{k}\ X\ B_2(\hat{j})=I_2LB_1\hat{i}=-(2A^2)\frac{L\mu_o}{2\pi d}\hat{i}$

Hence, due to this result you have that:

C. The left wire attracts the right wire and exerts as much force as the right wire does.

6 0

4 years ago

When charges qa, qb, and qc are placed respectively at the corners a, b, and c of a right triangle, the potential at the midpoin

earnstyle [38]

Answer:

8v

Explanation:

First we apply super position principle

Vt= v1 + v2+ v3

Remove qa

But vt= 20v

So V = v2+v3

V1= 20-15

= 5v

Remove qb

V= v1+v3

V=8v

So the potential when qa and qc are remove is the potential due to qb

Which is 8v

7 0

3 years ago

Help please

NARA [144]

Explanation:

help please

A lamp is marked 1.8w in normal brightness it carries a

3 0

3 years ago

As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens th

SSSSS [86.1K]

Answer:

The velocity of watermelon when it passes Superman is 78 m/s.

Explanation:

Height of the building, d = 320 m

Speed of the superman, v = 39 m/s

We need to find the speed of watermelon when it passes Superman. Let t is the time taken by the watermelon. So,

$d=ut+\dfrac{1}{2}gt^2$

Here u = 0

$d=\dfrac{1}{2}gt^2$

$39t=\dfrac{1}{2}\times 9.8\times t^2$

t = 7.95 seconds

Let v is the speed of the watermelon. It is given by :

$v=gt$

$v=9.8\times 7.95$

v = 77.91 m/s

or

v = 78 m/s

So, the velocity of watermelon when it passes Superman is 78 m/s.

3 0

3 years ago