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zhuklara [117]
3 years ago
15

In a chemical equation, the chemicals that react are considered . In a chemical equation, the chemicals that are produced are co

nsidered . In chemical equations, both sides of the equation must be ; if they are not, coefficients must be used.
Physics
2 answers:
vovangra [49]3 years ago
4 0

Answer

Hi,

In a chemical equation, chemicals that react are the reactants, while chemicals that are produced are the products/by products. Both sides of the equation must be balanced.

Explanation

When writing a chemical equation, reactants reacts to produce products. For example in the equation for formation of water, hydrogen combines with oxygen as 2H₂ +O₂→2H₂O where the first part before the arrow represent the reactants and the next part after the arrow are the products. Reactants are on the left where as products are on the right.Coefficient 2, in this cases is used for balancing the equation.

Good luck!

BartSMP [9]3 years ago
3 0
<h2>Answer: </h2>

<u>A chemical equation</u><u>  that shows the chemical formulas of substances that are reacting and the substances that are produced.</u>

<h2>Explanation:</h2>

A chemical equation should also be balanced on both sides. A chemical equation shows the substances involved in a chemical reaction . The substances that react are called reactants and the substances that are produced are called products.  A balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

For example

2 HCl + 2 Na → 2 NaCl + H 2

This equation will be counted  as two HCl plus two Na yields two NaCl and H two.

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A particle with charge -40.0nC is on the x axis at the point with coordinate x=0 . A second particle, with charge -20.0 nC, is on the x axis at x=0.500 m.

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A compound containing sodium and chlorine in a binary ionic compound would be named
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Quadrupling the power output from a speaker emitting a single frequency will result in what increase in loudness (in units of dB
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<em>6.02 dB increase  </em>

<em></em>

Explanation:

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imputing values of the intensity into the equation, we have

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