Vf = vi + at
0m/s = 40m/s + a(0.025s)
a = -1600m/s^2
Fnet = ma
Fnet = (0.10kg)(-1600m/s^2)
Fnet = -160 N
hope that helps
This is what I got:
Net force in the Y direction:
ΣFy = T1 - T2
F = ma
ma = T1 - T2
Isolate for T2
ma - T1 = -T2
Multiply by -1
T1 - ma = T2
100 - (3)(2) = T2
100 - 6 = T2
T2 = 94 N
Answer :
(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second
(21.4 second) - (72 second) = -50.6 second
Explanation :
(1) As we are given the expression :
(-3.7 meter/second) - (13.9 meter/second)
Now we have to evaluate this expression, we get:
⇒ -17.6 meter/second
(2) As we are given the expression :
(21.4 second) - (72 second)
Now we have to evaluate this expression, we get:
⇒ -50.6 second
Answer:
Same, the electric fields point in opposite directions and therefore cancel at some midpoint.
Explanation:
The Electric field net at some point between them is zero, only if they point in opposite direction (they cancel to the each other). In order the electric fields have opposite direction, at some point between the bees , the bees must have the same sign of electric charge
I would say D.) The ball bounces many times suggesting the energy is used up efficiently
