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Elena-2011 [213]
3 years ago
7

Can someone pls help me with this problem???

Physics
1 answer:
Katarina [22]3 years ago
8 0
Substitution is The answer
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A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to 52.0 km/h in the 18.0 s that it takes to round
zmey [24]

Answer:

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

Explanation:

According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential (a_{t}) and radial accelerations (a_{r}), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration (a), measured in meters per square second, is:

a = \sqrt{a_{r}^{2}+a_{t}^{2}} (Eq. 1)

Magnitudes of tangential and radial accelerations are determined by using the following formulas:

a_{t} = \frac{v_{f}-v_{o}}{t} (Eq. 1)

a_{r} = \frac{v_{f}^{2}}{R} (Eq. 2)

Where:

v_{o}, v_{f} - Initial and final speeds, measured in meters per second.

t - Time, measured in seconds.

R - Radius, measured in meters.

If we know that v_{o} = 24.444\,\frac{m}{s}, v_{f} = 14.444\,\frac{m}{s}, t = 18\,s and R = 120\,m, then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:

a_{t} = \frac{14.444\,\frac{m}{s}-24.444\,\frac{m}{s}  }{18\,s}

a_{t} = -0.556\,\frac{m}{s^{2}}

a_{r} = \frac{\left(14.444\,\frac{m}{s} \right)^{2}}{120\,m}

a_{r} = 1.739\,\frac{m}{s^{2}}

a = \sqrt{\left(-0.556\,\frac{m}{s^{2}} \right)^{2}+\left(1.739\,\frac{m}{s^{2}} \right)^{2}}

a \approx 1.826\,\frac{m}{s^{2}}

The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.

8 0
3 years ago
A space station, in the form of a spoked wheel 120 m in diameter, rotates to provide an artificial gravity of 3.00 m/s² for pers
lubasha [3.4K]

Answer:

2.12 rpm

Explanation:

a_c= Centripetal\ acceleration=3.00\ m/s^2\\r=radius=\frac {120}{2}=60\ m\\a_c=\frac {v^2}{r}\\\Rightarrow v^2=a_c\times r\\\Rightarrow v^2=3\times 60=180\\\Rightarrow v=\sqrt{180}=13.41\ m/s\\

v=\omega r\\\Rightarrow \omega=\frac {v}{r}\\\Rightarrow \omega=\frac {13.41}{60}\\\Rightarrow \omega=0.2236\ rad/s\\1\ rad/s=9.55\ rpm\\\Rightarrow 0.2236\ rad/s=2.12\ rpm\\\therefore Wheel\ rotations=2.12\ rpm

3 0
4 years ago
Mechanical energy is a term that is used to describe
Rudiy27

Answer is   B.  both potential and kinetic energy.

3 0
3 years ago
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In a shipping yard, a crane operator attaches a cable to a 1240-kg shipping container and then uses the crane to lift the contai
Firdavs [7]

Answer:

Explanation:

Given

mass of ship =1240 kg

height=37 m

(a)Work done by Tension in cable+work done by gravity =0

Work done by gravity =change in potential energy of mass=-1240\times 9.8\times 37=-449.624 kJ

Thus work done by tension=449.624 kJ

(b)work done by force of gravity=-mg\times h=-1240\times 9.8\times 37=-449.624 kJ

4 0
3 years ago
Read 2 more answers
3. Your friend says your body is made up of more than 99.9999% empty space. What do you think?
Nesterboy [21]

Answer:

I would agree with the statement. it's not just the body, but everything that we see is almost 99.9999% empty space

8 0
3 years ago
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