4 years ago

1.) dependent variable A.)the variable representing the

Physics

1 answer:

My name is Ann [436]4 years ago

4 0

Answer:

Explanation:

the answer is b

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Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak

Mashutka [201]

Answer:

Part a)

$\Delta \phi = 2.2 \pi$

Part b)

$f = 411.3 Hz$

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

$\Delta x = 3\sqrt2 - 3$

$\Delta x = 1.24 m$

now phase difference is related with path difference as

$\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)$

$\Delta \phi = \frac{2\pi}{\lambda}(1.24)$

here in order to find the wavelength

$\lambda = \frac{c}{f}$

$\lambda = \frac{340}{300} = 1.13$

now we have

$\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi$

Part b)

Now we know that when phase difference is odd multiple of $\pi$

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

$\Delta \phi = 3\pi$

so we have

$3\pi = \frac{2\pi}{\lambda}(1.24)$

so we have

$\lambda = 0.827$

now we have

$\frac{340}{f} = 0.827$

$f = 411.3 Hz$

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