<h2>Answer:</h2>
Moles of a gas = 0.500
Volume = 2.50 L
Pressure = 13. atm
Temperature = ?
Solution:
Formula:
PV = n RT
Putting the values in formula:
T = PV/nR = 13 * 2.5 / 0.5 * 0.082057
= 32.5/0.041 = 792.68 K
T = 792.68 K
We can't use the nitrogen present in the atmosphere although 80% of the atmosphere consists of nitrogen only.We get this from the plants called as leguminous plants which can convert or fix atmospheric nitrogen into usable ones..
Answer:

Explanation:
Hello,
In this case, the undergoing chemical reaction is:

Next, we identify the limiting reactant by computing the available moles of ethane and the moles of ethane consumed by 60.0 grams of oxygen:

Thus, we notice there are less available moles, for that reason, the ethane is the limiting reactant. Finally, we can compute the produced moles of water by:

Best regards.