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Alchen [17]
3 years ago
9

Which of the following molecules may diffuse freely through a phospholipid bilayer? (select two answers) asparagine, an amino ac

id with a large, hydrophilic side chain alanine, an amino acid with a small, hydrophobic side-chain testosterone, a steroid hormone fructose, a monosaccharide molecular oxygen (O2)
Chemistry
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

testosterone, a steroid hormone

molecular oxygen (O₂)

Explanation:

Phospholipid Bi layer is permeable to some molecules and it will allow them to pass through it freely. Molecules which are soluble in water (polar molecules or hydrophillic molecules) are less permeable through phospholipid Bi layer . In given options Molecular Oxygen and Testosterone( steroid Hormone) are permeable through the layer because of its lipid solubility and size of the molecule .

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1. What is the molarity of a solution prepared by dissolving 3.11 grams of NaOH in
Elena L [17]

The molarity of a solution prepared by dissolving 3.11 grams of NaOH in

enough water to make 300 milliliters of solution is 0. 256 mol/ L

Explanation:

<h3>What is Molarity?</h3>

Molarity (M) is the amount of a substance in a given volume of solution. It is otherwise known as the number of moles of solute in a certain amount of solution.

The unit of molarity is mol/L

<h3>Formula for calculating molarity :</h3>

Molarity = number of moles of solute divided by the volume of the solution\

<h3>Parameters </h3>

Molarity = ?

Number of  moles is calculated using :

Mass of the solute = 3.11 grams of NaOH

Molar mass of the solute = Na + O + H

Let's input the atomic numbers of the elements: Na (23) , O (16) , H (1)

Molar mass of NaOH = 23 + 16 + 1 = 40 g/ mol

Number of moles = 3.11 ÷ 40 = 0.077 mol

Volume of the solution is measured in Liters

Let's convert 300 milliters to liters = 300 divided by 1000 = 0.3 Liters

Molarity = 0.077 ÷ 0.3 = 0. 256 mol/ L

Therefore, the Molarity of the solution is 0. 256 mol/ L

Read more on molarity here :

brainly.com/question/26873446

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2 years ago
Solid cadmium sulfide reacts with an aqueous solution of sulfuric acid . Express your answer as a balanced chemical equation. Id
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Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

          CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)

Hence, ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)

Therefore, net ionic equation for this reaction is as follows.

      CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)

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Valence electrons are important because these are the only electrons involved with an atom's
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