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Alchen [17]
3 years ago
9

Which of the following molecules may diffuse freely through a phospholipid bilayer? (select two answers) asparagine, an amino ac

id with a large, hydrophilic side chain alanine, an amino acid with a small, hydrophobic side-chain testosterone, a steroid hormone fructose, a monosaccharide molecular oxygen (O2)
Chemistry
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

testosterone, a steroid hormone

molecular oxygen (O₂)

Explanation:

Phospholipid Bi layer is permeable to some molecules and it will allow them to pass through it freely. Molecules which are soluble in water (polar molecules or hydrophillic molecules) are less permeable through phospholipid Bi layer . In given options Molecular Oxygen and Testosterone( steroid Hormone) are permeable through the layer because of its lipid solubility and size of the molecule .

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Neon is an inner gas because it’s outer ____ is full of electrons.
Fynjy0 [20]

Answer:

Neon is an inner gas because it’s outer <u>__shell__</u> is full of electrons.

7 0
3 years ago
25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are
geniusboy [140]

The new concentrations of HClO and NaClO are  0.25M and 19M

Calculation of number of moles of each component,

Molarity of HClO = number of moles/volume in lit =  0. 500 M

Number of moles = molarity  of HClO× volume in lit = 0. 500 M× 0.025 L

Number of moles of HClO = 0.0125 mole

Molarity of NaClO  = number of moles/volume in lit =  0. 38 M

Number of moles = molarity of NaClO × volume in lit = 0. 38 M× 0.025 L

Number of moles of  NaClO  = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of HClO = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of HClO = 0.25M

Molarity of NaClO  = number of moles/volume in lit = 0.95mole/0.05L

Molarity of NaClO  = 19 M

learn about  Molarity

brainly.com/question/8732513

#SPJ4

5 0
1 year ago
What atom is the smallest size? A. Li B. Be C. F D. C
s2008m [1.1K]

Answer:

A

Explanation:

lies to the left of periodic table

7 0
3 years ago
What was the result of collisions between the early Earth and other, smaller protoplanets?
RoseWind [281]

The trajectory of their motion knocked the Earth into a different orbit.

3 0
3 years ago
A 30.0-g piece of metal at 203oC is dropped into 400.0 g of water at 25.0 oC. The water temperature rises to 29.0 oC. Calculate
oee [108]

The specific heat of the metal is 2.4733 J/g°C.

Given the following data:

  • Initial temperature of water = 25.0°C
  • Final temperature of water = 29.0°C
  • Mass of water = 400.0 g
  • Mass of metal = 30.0 g
  • Temperature of metal = 203.0°C

We know that the specific heat capacity of water is 4.184 J/g°C.

To find the specific heat of the metal (J/g°C):

Heat lost by metal = Heat gained by water.

Q_{metal} = Q_{water}

Mathematically, heat capacity or quantity of heat is given by the formula;

Q = mc\theta

<u>Where:</u>

  • Q is the heat capacity or quantity of heat.
  • m is the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Substituting the values into the formula, we have:

30(203)c = 400(4.184)(29 \; -\; 20)\\\\6090c = 1673.6(9)\\\\6090c = 15062.4\\\\c = \frac{15062.4}{6090}

Specific heat capacity of metal, c = 2.4733 J/g°C

Therefore, the specific heat of the metal is 2.4733 J/g°C.

Read more: brainly.com/question/18691577

8 0
2 years ago
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