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dezoksy [38]
3 years ago
6

A 50 g bullet is fired into a 2 kg ballistic gel at rest on a frictionless surface. The bullet embeds itself in the gel and begi

ns moving at 3.5 m/s. What was the initial velocity of the bullet?
Physics
2 answers:
expeople1 [14]3 years ago
5 0
The answer would be 1200m/s
Elenna [48]3 years ago
5 0

Explanation:

The initial velocity of the bullet was 3.5m per sec because on a frictionless surface a bullet can't be stopped as there is no force opposing the bullet and as the bullet must be fired in certain velocity, we can say that the initial velocity of the bullet was 3.5mper sec.

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A field researcher uses the slow-motion feature on her phones camera to shoot a video of an eel spinning at its maximum rate. Th
posledela

Answer:

\alpha=(1/120)*14*360=42degrees

Explanation:

Eels have been recorded to spin at up to 14 revolutions per second when feeding in this way

So the angle the eel rotate is going to be

Camera record 120 frames per second

time taken for 1 frame record

t_t= 1/120 seconds

eel rotates

\alpha_1=14rev *360degrees in 1 second

so:

eel rotetas \alpha=(1/120)*14*360=42degrees

5 0
4 years ago
The 10-lb block A attains a velocity of 2ft/s in 5 seconds, starting from rest. Determine the tension in the cord and the coeffi
Nezavi [6.7K]

Answer:

Explanation:

Let T be the tension in the cord.

Impulse by cord = change in momentum of block A .

T x 5s = 10 ( 2 -0) = 20

T = 4 poundal .

acceleration of block B = 2 / 5 = 0.4 m /s²

Net force applied on A = m ( g + a ) where m is mass of block B , a is acceleration of block B .

= 8 ( 32 + .4 ) = 259.2 poundal

Frictional force on block A = 259.2 - 4 = 255.2 poundal

μ x 10 x 32 = 255.2

320μ = 255.2

μ =0 .8 .

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