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dezoksy [38]
3 years ago
6

A 50 g bullet is fired into a 2 kg ballistic gel at rest on a frictionless surface. The bullet embeds itself in the gel and begi

ns moving at 3.5 m/s. What was the initial velocity of the bullet?
Physics
2 answers:
expeople1 [14]3 years ago
5 0
The answer would be 1200m/s
Elenna [48]3 years ago
5 0

Explanation:

The initial velocity of the bullet was 3.5m per sec because on a frictionless surface a bullet can't be stopped as there is no force opposing the bullet and as the bullet must be fired in certain velocity, we can say that the initial velocity of the bullet was 3.5mper sec.

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An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

                                      a = (v - u) / t   m/s²

       ∴                              t = (v - u) / a

                                         = (0 - 54) / (-6.8)

                                         = 7.94 s

The average velocity of the object,

                                       V = (54 + 0)/2

                                           = 27 m/s

The displacement of the object,

                                 d = V x t   meter

                                    = 27 x 7.94

                                    = 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

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3 years ago
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Answer:

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