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dezoksy [38]
3 years ago
6

A 50 g bullet is fired into a 2 kg ballistic gel at rest on a frictionless surface. The bullet embeds itself in the gel and begi

ns moving at 3.5 m/s. What was the initial velocity of the bullet?
Physics
2 answers:
expeople1 [14]3 years ago
5 0
The answer would be 1200m/s
Elenna [48]3 years ago
5 0

Explanation:

The initial velocity of the bullet was 3.5m per sec because on a frictionless surface a bullet can't be stopped as there is no force opposing the bullet and as the bullet must be fired in certain velocity, we can say that the initial velocity of the bullet was 3.5mper sec.

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Sound intensity = 1/(r^2)

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A 180 cm length of string has a mass of 5.0 g. it is stretched with a tension of 8.6 n between fixed supports. (a) what is the w
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3 years ago
An object is thrown from the ground with an initial velocity of 30 m/s. What is the velocity at the point 25 m above the ground?
dsp73

Answer:

It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.

V^2=U^2+2*a*x

V=0 (as it is at max height)

U=30ms^-1 (initial speed)

a=-g /-9.8ms^-2 (as it is moving against gravity)

x is the variable you want to calculate (height)

0=30^2+2*(-9.8)*x

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3 0
2 years ago
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Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

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where

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Here we have

\theta=40^{\circ}

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I_2=I_1 (cos 40^{\circ})^2=0.587I_1

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I_2=0.587 (\frac{I_0}{2})=0.293I_0

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2 years ago
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I need the picture to answer the question

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