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Scrat [10]
3 years ago
8

In scientific notation, 0.00074m can be written as 1- 0.74×10‐³m 2- 7.4×10-⁴m 3- 74×10‐⁵m 4- 740×10‐⁶m

Physics
1 answer:
Maru [420]3 years ago
8 0

Answer:

0.00074m = 7.4*10^{-4}m

Explanation:

Given

0.00074m

Required

Express as scientific notation

The scientific notation of a number is: a * 10^{b}

Where 1 \le a \le 9

This implies that:

0.00074m = 7.4 * 10^b

Next, is to determine the value of b.

Count the number of point to move from the current point location to 7.4.

If the point moves backward, b will be negative, else b will be positive.

So:

0.00074m      b=-4

Hence:

0.00074m = 7.4*10^{-4}m

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Based on observations, the speed of a jogger can be approximated by the relation v 5 7.5(1 2 0.04x) 0.3, where v and x are expre
castortr0y [4]

Answer:

solution:

to find the speed of a jogger use the following relation:  

V

=

d

x

/d

t

=

7.5

×m

i

/

h

r

...........................(

1

)  

in Above equation in x and t. Separating the variables and integrating,

∫

d

x

/7.5

×=

∫

d

t

+

C

or

−

4.7619  

=

t

+

C

Here C =constant of integration.   

x

=

0  at  t

=

0

, we get:  C

=

−

4.7619

now we have the relation to find the position and time for the jogger as:

−

4.7619  =

t

−

4.7619

.

.

.

.

.

.

.

.

.

(

2

)

Here

x  is measured in miles and  t  in hours.

(a) To find the distance the jogger has run in 1 hr, we set t=1 in equation (2),    

     to get:

      = −

4.7619  

      =  

1

−

4.7619

      = −

3.7619

  or  x

=

7.15

m

i

l

e

s

(b) To find the jogger's acceleration in   m

i

l

/

differentiate  

     equation (1) with respect to time.

     we have to eliminate x from the equation (1) using equation (2).  

     Eliminating x we get:

     v

=

7.5×

     Now differentiating above equation w.r.t time we get:

      a

=

d

v/

d

t

       =

−

0.675

/

      At  

      t

=

0

      the joggers acceleration is :

       a

=

−

0.675

m

i

l

/

        =

−

4.34

×

f

t

/  

(c)  required time for the jogger to run 6 miles is obtained by setting  

        x

=

6  in equation (2).  We get:

        −

4.7619

(

1

−

(

0.04

×

6  )

)^

7

/

10=

t

−

4.7619

         or

         t

=

0.832

h

r

s

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