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Scrat [10]
3 years ago
8

In scientific notation, 0.00074m can be written as 1- 0.74×10‐³m 2- 7.4×10-⁴m 3- 74×10‐⁵m 4- 740×10‐⁶m

Physics
1 answer:
Maru [420]3 years ago
8 0

Answer:

0.00074m = 7.4*10^{-4}m

Explanation:

Given

0.00074m

Required

Express as scientific notation

The scientific notation of a number is: a * 10^{b}

Where 1 \le a \le 9

This implies that:

0.00074m = 7.4 * 10^b

Next, is to determine the value of b.

Count the number of point to move from the current point location to 7.4.

If the point moves backward, b will be negative, else b will be positive.

So:

0.00074m      b=-4

Hence:

0.00074m = 7.4*10^{-4}m

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A cat has a mass of 3 kg and runs at a speed of 6 m/s. how much kinetic energy does the cat have?
RUDIKE [14]
We have: K.E. = 1/2 mv²
Here: m = 3 Kg
v = 6 m/s

Substitute their values, 
K.E. = 1/2 * 3 * 6²
K.E. = 1/2 * 3 * 36
K.E. = 54 J

In short, Your Answer would be 54 Joules

Hope this helps!
4 0
3 years ago
The process in which acids and bases react so that the properties of both are lost to form water and a salt is called __________
makvit [3.9K]
The process is called neutralization.
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What animal did wolfgang kohler use to study insight learning
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3 years ago
A photon ionizes a hydrogen atom from the ground state. The liberated electron 11. recombines with a proton into the first excit
anygoal [31]

Answer:

a) 23.2 e V

b) energy of the original photon is 36.8 eV

Explanation:

given,

energy at ground level = -13.6 e V

energy at first exited state = - 3.4 e V

A photon of energy ionized from ground state and electron of energy K is released.

h ν₁ - 13.6 = K

K combine with photon in first exited state giving out photon of energy

h\nu_2 =\dfrac{hc}{\lambda}=\dfrac{12400}{466}

            = 26.6 e V

h c = 6.626 ×  10⁻³⁴ ×  3  × 10⁸  = 12400 e V A°

K + ( 3.4 ) = 26.6 e V

a) energy of free electron

K = 26.6 - 3.4 = 23.2 e V

b) energy of the original photon

h ν₁ - 13.6 = K

h ν₁  = 23.2 + 13.6

       = 36.8 e V

energy of the original photon is 36.8 eV

3 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
abruzzese [7]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 3.4 \times 25

\sf \implies KE =3.4 \times 25

\sf \implies KE = 85 \: J

8 0
3 years ago
Read 2 more answers
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