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Mandarinka [93]
3 years ago
14

What is the total number of pounds of carbon dioxide that 2 trees remove from the air each year?

Physics
2 answers:
Vikentia [17]3 years ago
5 0

Answer:

On average, one acre of new forest can sequester about 2.5 tons of carbon annually. Young trees absorb CO2 at a rate of 13 pounds per tree each year. Trees reach their most productive stage of carbon storage at about 10 years at which point they are estimated to absorb 48 pounds of CO2 per year.

Klio2033 [76]3 years ago
5 0
2.5 tons every year I think
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MA_775_DIABLO [31]

Answer:

oh your questions are not a question lol

qwaesrzdxftcghyhvbjuinkoplmbfaeaiufkkjfausoyiatiatuafaftaeoaklsoysotsgxfllylstltysosttstodholhcyptysptspudpyttywptwtfihfhufhpvuo

Explanation:

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3 0
3 years ago
A charged particle enters a uniform magnetic field B with a velocity v at right angles to the field. It moves in a circle with p
alukav5142 [94]

A) d. 10T

When a charged particle moves at right angle to a uniform magnetic field, it experiences a force whose magnitude os given by

F=qvB

where q is the charge of the particle, v is the velocity, B is the strength of the magnetic field.

This force acts as a centripetal force, keeping the particle in a circular motion - so we can write

qvB = \frac{mv^2}{r}

which can be rewritten as

v=\frac{qB}{mr}

The velocity can be rewritten as the ratio between the lenght of the circumference and the period of revolution (T):

\frac{2\pi r}{T}=\frac{qB}{mr}

So, we get:

T=\frac{2\pi m r^2}{qB}

We see that this the period of revolution is directly proportional to the mass of the particle: therefore, if the second particle is 10 times as massive, then its period will be 10 times longer.

B) a. f/10

The frequency of revolution of a particle in uniform circular motion is

f=\frac{1}{T}

where

f is the frequency

T is the period

We see that the frequency is inversely proportional to the period. Therefore, if the period of the more massive particle is 10 times that of the smaller particle:

T' = 10 T

Then its frequency of revolution will be:

f'=\frac{1}{T'}=\frac{1}{(10T)}=\frac{f}{10}

6 0
3 years ago
Choose the scenario in which the sound frequency of the waves is higher.
mrs_skeptik [129]

Answer:

B) the sound source moves towards you at 100 m/sec

Explanation:

The Dopper Effect is a phenomenon that occur when there is relative motion between an observer and a source of a wave. When this situation occurs, there is an apparent shift in frequency of the wave, as observed by the observer.

The apparent frequency observed by the observer is given by

f'=\frac{v\pm v_o}{v\pm v_s}f

where

f is the original frequency of the wave

f' is the apparent frequency

v is the speed of the wave

v_o is the velocity of the observer (positive if moving towards the source of the wave, negative otherwise)

v_s is the velocity of the source (negative if moving towards from the observer, positive otherwise)

In this problem, we want to find the scenario in which the sound frequency is higher.

We see that in all 4 scenarios, the sound source is moving: this means we have to find the scenario in which the denominator of the equation is smaller.

First of all, we notice the sound source moves towards the observer, v_s is negative, so the denominator is higher: this means that the correct option must be either A or B.

Also, we notice that since v_s is negative, a value larger in magnitude will mean a smaller denominator: therefore, the correct answer will be

B) the sound source moves towards you at 100 m/sec

Since this situation will make the denominator of the formula the smallest possible.

5 0
3 years ago
Answer choices
marshall27 [118]

Answer:

Option-C (Lipoprotein profile)

4 0
2 years ago
Is vapor pressure independent of atmospheric pressure? - This is what my instructor told me, but I don't understand why. ...?
miss Akunina [59]
Vapor pressure<span> or equilibrium </span>vapor pressure<span> is defined as the </span>pressure<span> exerted by a </span>vapor<span> in thermodynamic equilibrium with its condensed phases at a certain temperature. It is independent with atmospheric pressure since it does not change by changing the atmospheric pressure only. </span>
5 0
4 years ago
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