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ICE Princess25 [194]
4 years ago
11

If the Sun were to mysteriously turn into a black hole (don't worry . . . it won't!) and retain its current mass, what would hap

pen to Earth? A. Earth would be pulled in within minutes. B. Earth would be pulled in over many years. C. Earth would continue to orbit the Sun as usual. D. Earth would orbit the Sun just outside the event horizon.
Physics
1 answer:
galina1969 [7]4 years ago
3 0
If the Sun were to turn into a black hole, or be replaced by a black hole
with the same mass as the Sun, then Earth would continue to orbit it
as usual.  (But it would be very cold and dark around here.)
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A 200g piece of iron is heated at 100C. It is than dropped into water to bring its temperature down to 22C. What is the amount o
gizmo_the_mogwai [7]

Answer:

6926.4J

Explanation:

Given parameters:

Mass of iron  = 200g

Initial temperature  = 100°C

Final temperature  = 22°C

Unknown:

Amount of heat transferred to the water  = ?

Solution:

The quantity of heat transferred to the water is a function of mass and temperature of the iron;

 H  = m c Ф

m is the mass of the iron

Ф is the change in temperature

C is the specific heat capacity of iron = 0.444 J/g°C

Now;

 insert the parameters and solve;

      H  = 200 x 0.444 x (100-22)

      H = 6926.4J

8 0
3 years ago
You lift a 45N bag of mulch? 1.2meters and carry it a distance of 10 meters how much work was done
Anettt [7]
W = Fxd
However, when you carry it, the actual bag of mulch isnt changing height so the only work done on the actual bag is when you lift it.
W = 45N x 1.2m
= 54J
7 0
4 years ago
What three variable factors determine the force of gravity between any two objects
zalisa [80]
The force of gravity between two objects is:
F = G*m1*m2/r^2

So, it is dependent of the two masses and the distance between their centers of mass.

If, you are referring to the force of gravity due to the earth, then the two factors are the mass of the object and the distance from the center of mass of the object and center of mass of the earth.
5 0
3 years ago
Read 2 more answers
Un ladrillo se le imparte una velocidad inicial de 6m/s en su trayectoria hacia abajo. ¿cual sera su velocidad final despues de
nirvana33 [79]
Hola!

Respuesta:

28,64 m/s.

Explicación:

Datos:

Vo: 6 m/s 
Altura o distancia recorrida: 40 m
Gravedad: 9,81 m/s²

El ejercicio puede ser resuelto facilmente utilizando la siguiente formula:

Vf²-Vo²=2×g×h.

Es importante hacer notar que al estar lanzando el ladrilo hacia abajo, el sentido del movimiento sigue el sentido de la gravedad, es decir es necesario que tomes el valor de la gravedad como positivo (+) y no negativo (-) como normalmente se usa.

Sustituyendo se tiene:

Vf
²= (6 m/s)²+ (2)×(9,81 m/s²)x(40m)
Vf²=820,8 m²/s²
√Vf²=√820,8 m²/s² 
Vf= 28,64 m/s

Que tengas un buen día!


4 0
4 years ago
PLEASE HELPPP ILL DO ANYTHINGGGGGG Write 1 paragraph or more and use all three of Newton’s laws of motion to describe what happe
Lilit [14]

Answer:

The image shows an object at rest, then a force pushes the car into the water. Newton's First Law describes that objects at rest remain at rest, and objects at motion remain at motion, unless they are bothered by a force. This law comes into play with the image because the object is first seen at rest, on the top of another object. Then it is seen falling, and is now in motion at it descends into the water. Newton's Second Law, F = MA, is seen in the image is the object accelerates into the water from the force. Newton's Third Law, which states 'for every action there is an equal but opposite reaction', is in this image as the object is falling, then makes contact with the water.

Explanation: Newton's Laws

4 0
3 years ago
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