-0 m/s
- average velocity=displacement/time
- the runners displacement is zero so her average velocity must be zero
The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
<h3>Electric field on the master charge</h3>
E = kq/r²
where;
- q is magnitude of master charge
- r is distance of separation
- k is Coulomb's constant
E = (9 x 10⁹ x 0.63)/(0.75²)
E = 1.008 x 10¹⁰ N/C
<h3>Force on the test charge</h3>
F = Eq
where;
- E is electric field
- q is the test charge
F = (1.008 x 10¹⁰) x (0.5)
F = 5.04 x 10⁹ N
Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
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Answer:
1.984 m/s^2
Explanation:
initial velocity of air craft, u = 0 m/s
final speed of the aircraft, v = 120 km/h
Convert the speed into m/s from km/h
So, v = 120 km/h = 33.33 m/s
distance, s = 280 m
Let a be the acceleration of the aircraft.
Use third equation of motion
a = 1.984 m/s^2
Thus, the acceleration of the aircraft is 1.984 m/s^2.
Answer:
0
Explanation:
Defining velocity :
Velocity is a vector which is the ratio of a person's total displacement with time.
Displacement, in simple terms refers to the distance between an individual's initial position to his final position.
Man's initial position = House
After all his navigation and points covered irrespective of the distance ;
Final position = House
Hence, we can conclude that the man's Displacement is ;
Final position - Initial position = 0
Hence,
Velocity = Displacement / time taken
Velocity = 0 / 3
Velocity = 0
