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Oksanka [162]
4 years ago
12

Solve for y. 5x-10y=-40

Mathematics
2 answers:
marusya05 [52]4 years ago
4 0
Y=4


-10/-10 = -40/-10 

-40/-10 = 4
Andru [333]4 years ago
4 0
This is the answer x = 8 + 2y

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Simplify 1)  root 45 - 3 root 20 +4 Root 5 plzz write the sum
BARSIC [14]
= root 45 - 3 root 20 + 4 root 5
= root 9 * root 5 - 3 * root 4 * root 5 + 4 root 5
=3 root 5 - 3 * 2 * root 5 + 4 root 5
= root 5 ( 3 - 6 + 4 )
= root 5 *1
= root 5
3 0
3 years ago
Given: m∠AKB = 25°
dexar [7]

Answer:

V = 255.98189 pi

SA = 172.64114π

Step-by-step explanation:

The first thing to do is find the radius.

the measure of angle AKO = 1/2 the measure of angle AKB

m< AKO = 12.5 degrees

Now use trig to find AO (aka the radius)

tan(12.5) = AO/25

AO = 25* tan(12.5)

<em>I'm leaving it like this to get a more accurate number</em>

Now to find the volume

the volume of a cone is pir^2h/3

plugging everything in we get:

pi(25*tan(12.5))^2 * 25/3

which is about <u>255.98189 pi</u>

Now for surface area

(this is the moment I realize symbols exist)

SA = πr(r+√h²+r²)

plugging everything in we have

π(25tan(12.5))((25tan(12.5)+√625+(25tan(12.5))^2)

<em>I know it looks like a lot but that's mainly because I left the radius as 25tan(12.5)</em>

The Surface Area is about <u>172.64114π</u>

8 0
3 years ago
M1=28 degrees, m6=65 degrees, m5=65 degrees. Find mMAX.
viva [34]

Answer:

D. 93

Step-by-step explanation:

Given:

m<1 = 28°

m<6 = 65°

m<5 = 65°

Required:

m<MAX

Solution:

m<MAX = m<1 + m<5 (angle addition postulate)

Substitute

m<MAX = 28° + 65°

m<MAX = 93°

4 0
3 years ago
I need help with this question i dont feel like working it out please help :|
bezimeni [28]

Answer:

B. 26

Step-by-step explanation:

3 0
3 years ago
Write the equation in Slope - intercept form by solving for y. 2x+3y=12
Gennadij [26K]

y=-2/3x+4 i hope this helps!

7 0
3 years ago
Read 2 more answers
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