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Oksanka [162]
4 years ago
12

Solve for y. 5x-10y=-40

Mathematics
2 answers:
marusya05 [52]4 years ago
4 0
Y=4


-10/-10 = -40/-10 

-40/-10 = 4
Andru [333]4 years ago
4 0
This is the answer x = 8 + 2y

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A square picture with side length 30 cm is scaled by 60% on a photocopier the copy is then scaled by 60% again. What is the side
Sonja [21]

Answer:

10.8 cm

Step-by-step explanation:

we know that

1) A square picture with side length 30 cm is scaled by 60% on a photocopier

Remember that

60\%=60/100=0.60

so

The length of the first copy of the picture is

30(0.60)=18\ cm

2) The copy is then scaled by 60% again

so

The length of the second copy of the picture is

18(0.60)=10.8\ cm

4 0
3 years ago
a new car is purchased for $17,900 the value of the car depreciates at 13% per year what will the value of the car be to the nea
liberstina [14]

Answer:

The value of the car would be 6753

Explanation

<u>Year     | Value <   |  Deprec. | Balance</u>

Year 1 17900 2327 15573

Year 2 15573 2024 13549

Year 3 13549 1761          11787

Year 4 11787 1532 10255

Year 5 10255 1333 8922

Year 6 8922 1160         7762

Year 7 7762 1009 6753

https://goodcalculators.com/percentage-depreciation-calculator/ - Where I got your answer if you have more problems like this!

3 0
4 years ago
Prove the identity 2csc2x=csc^2xtanz
Verizon [17]

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

2 \csc(2x)  =  \csc {}^{2} (x)  \tan(x)

2 \frac{1}{ \sin(2x) }  =  \csc {}^{2} (x)  \tan(x)

2  \times \frac{1}{2 \sin(x)  \cos(x) }  =  \csc {}^{2} (x)  \tan(x)

\frac{1}{ \sin(x) \cos(x)  }  =   \csc {}^{2} (x)  \tan(x)

\csc(x)  \sec(x)  =  \csc {}^{2} (x)  \tan(x)

Consider the RHS

\csc(x)  \sec(x)  =( 1 +  \cot {}^{2} (x) ( \tan(x))

\csc(x)  \sec(x)  =  \tan(x)  +  \cot(x)

\csc(x)  \sec(x)  =  \frac{ \sin(x) }{ \cos(x) }  +  \frac{ \cos(x) }{ \sin(x) }

\csc(x)  \sec(x)  =  \frac{1}{ \sin(x) \cos(x)  }

\csc(x)  \sec(x)  =  \csc(x)  \sec(x)

7 0
2 years ago
A red candle is 8 inches y'all and burns at a rate of 7 divided by 10 inch per hour. A blue candle is 6 inches tall and burns at
lorasvet [3.4K]

Answer:

Both candles will have the same height after 4 hours.

Step-by-step explanation:

The equation for the amount of candle remaining can be given by the following equations:

Q(t) = Q(0) - at

In which Q(t) is the amount after t hours, Q(0) is the initial amount and a is how much it decreases, in inches, per hour.

Red candle:

8 inches tall and burns at a rate of 7 divided by 10 inch per hour. This means that Q(0) = 8, a = 7/10 = 0.7. So

Q_{r}(t) = 8 - 0.7t

Blue candle:

6 inches tall and burns at a rate of 1 divided by 5 inch per hour. This means that Q(0) = 6, a = 1/5 = 0.2. So

Q_{b}(t) = 6 - 0.2t

After how many hours will both candles be the same height ?

This is t when

Q_{r}(t) = Q_{b}(t)

8 - 0.7t = 6 - 0.2t

0.2t - 0.7t = 6 - 8[/yrc][tex]-0.5t = -2

Multiplying by (-1)

0.5t = 2

t = \frac{2}{0.5}

t = 4

Both candles will have the same height after 4 hours.

6 0
4 years ago
Could someone please help
myrzilka [38]
19 x 4 is the equation and the answers is 76
8 0
4 years ago
Read 2 more answers
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