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Oksanka [162]
3 years ago
12

Solve for y. 5x-10y=-40

Mathematics
2 answers:
marusya05 [52]3 years ago
4 0
Y=4


-10/-10 = -40/-10 

-40/-10 = 4
Andru [333]3 years ago
4 0
This is the answer x = 8 + 2y

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Ahat [919]

Answer:

5.14 Decameters

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3 0
3 years ago
Claire is putting up a fence around her rectangular garden. The length is four less than double the width. The perimeter is 22 f
Doss [256]

Answer:

The dimensions are 6 by 5 feet.

Length = 6 feet.

Width = 5 feet.

Step-by-step explanation:

Let the length = L

Let the width = W

Perimeter of a rectangle = 2L + 2W

Translating the word problem into an algebraic equation, we have;

L = 2W - 4 ........equation 1

22 = 2L + 2W .......equation 2

Substituting the value of "L" into equation 2, we have;

22 = 2(2W - 4) + 2W

22 = 4W - 8 + 2W

22 + 8 = 6W

30 = 6W

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To find the length, L

Substituting the value of "W" into equation 1, we have;

L = 2W - 4

L = 2(5) - 4

L = 10-4

Length, L =6 feet

Therefore, the dimensions of the garden are 6 by 5 feet.

5 0
3 years ago
Fill the missing number to make each expression equal. +2=16+3?
WARRIOR [948]

Answer:

14

Step-by-step explanation:

14+2=16+3

3 0
3 years ago
What's the quadratic formula?
lesantik [10]
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6 0
3 years ago
Help center of circle
Lelu [443]

Answer:

Center = (7, - 5)

Radius = 3

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  + 14x - 10y + 65 = 0 \\  {x}^{2}  + 14x +  {y}^{2}  - 10 + 65 = 0 \\ ( {x}^{2}  + 14x +  {7}^{2})  -  {7}^{2}  +  ({y}^{2}  - 10y +  {5}^{2})  \\-  {5}^{2}  + 65 = 0 \\ (x + 7)^{2}  + (y - 5)^{2}  - 49 - 25 + 65 = 0 \\  (x + 7)^{2}  + (y - 5)^{2}  - 49  + 40= 0 \\   (x + 7)^{2}  + (y - 5)^{2}  - 9= 0 \\   (x + 7)^{2}  + (y - 5)^{2}   =  9 \\  (x + 7)^{2}  + (y - 5)^{2}   =   {3}^{2}  \\  equating \: it \: with \: \\ (x  -  h)^{2}  + (y - k)^{2}   =   {r}^{2}  \\  - h = 7 \implies \: h =  - 7 \\  - k =  - 5 \implies \: k = 5 \\ center = ( - h, \:  - k)  = (7, \:  \:  - 5) \\  \\ radius \: r = 3

7 0
3 years ago
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