The value of m<span> must be greater than the value of</span><span> n</span><span>. When you multiply the binomials, the middle term is the result of combining the outside and inside products. So, </span>bx<span> = –</span>nx<span> + </span>mx<span>, or </span>bx<span> = (–</span>n<span> + </span>m)x<span>. This means that </span>b<span> = –</span>n<span> + </span>m<span>. When adding numbers with opposite signs, you subtract their absolute values, and keep the sign of the number having the larger absolute value. Since </span>b<span> is positive, </span>m<span>must have the larger absolute value.</span>
Answer:
Step-by-step explanation:
Y= 5/2x+5. :D
Answer:
x = 100
Step-by-step explanation:
The area of the left square is 3600
A =s^2
3600 = s^2
Taking the square root of each side
60 =s
The area of the right square is 1600
A =s^2
1600 = s^2
Taking the square root of each side
40 =s
Adding the lengths
60+40 =x
100 =x
I will be using the language C++. Given the problem specification, there are an large variety of solving the problem, ranging from simple addition, to more complicated bit testing and selection. But since the problem isn't exactly high performance or practical, I'll use simple addition. For a recursive function, you need to create a condition that will prevent further recursion, I'll use the condition of multiplying by 0. Also, you need to define what your recursion is.
To wit, consider the following math expression
f(m,k) = 0 if m = 0, otherwise f(m-1,k) + k
If you calculate f(0,k), you'll get 0 which is exactly what 0 * k is.
If you calculate f(1,k), you'll get 0 + k, which is exactly what 1 * k is.
So here's the function
int product(int m, int k)
{
if (m == 0) return 0;
return product(m-1,k) + k;
}
