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Andre45 [30]
3 years ago
13

Each week Quentin earns $30. If he saves this money, create a graph that shows the total amount of money Quentin has saved from

week 1 through week 8. Write an equation that represents the relationship between the number of weeks that Quentin has saved his money, w, and the total amount of money in dollars that he has saved, s. Then, name the independent and dependent variables. Write a sentence that shows this relationship.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer: s = 30w

graph attached

Step-by-step explanation:

Quentin earns $30/week

w = weeks

s = saved money

s = 30w

s depends on w. Each week he adds $30 to his total amount, so to know how much money he has in the end of each week, we need to multiply 30 by the number of the week.

independent variable = w

dependent variable = s

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Maurinko [17]

Answer:

14,400

12 square = 144

10 square = 100

144*100

= 14,400

8 0
2 years ago
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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

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\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

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\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
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Me zachary brings 264 ounces of water to basketball practice for the players to drink . Ifmr zachary didvides the water equally
Mila [183]

Answer:

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Step-by-step explanation:

We have been given that Me Zachary brings 264 ounces of water to basketball practice for the players to drink. Mr Zachary divides the water equally among the 9 players. We are asked to find the amount of water that is left over.

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Let us divide 264 by 9.

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    <u>   18</u>

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<u>          81</u>

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3 years ago
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Veronika [31]

Answer:

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We can perform the same calculation here,

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almond37 [142]
The answer to "6k+2" if "k=1.3" is "9.8".
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