8.4617....
Hope this helped you :)
Answer:
Step-by-step explanation:
T = 4c + 25....where c = # of classes and T = total cost
2 classes...so sub in 2 for c and solve for T
T = 4(2) + 25
T = 8 + 25
T = 33 <==== with 2 classes ,its $ 33
4 classes....so sub in 4 for c and solve for T
T = 4(4) + 25
T = 16 + 25
T = 41 <==== with 4 classes, its $ 41
8 classes....sub in 8 for c
T = 4(8) + 25
T = 32 + 25
T = $ 57 <==== with 8 classes, its $ 57
10 classes...sub in 10 for c
T = 4(10) + 25
T = 40 + 25
T = 65 <===== with 10 classes, its $ 65
Answer:
area: 41.04 cm² ; perimeter 35.8 cm
Step-by-step explanation:
Perimeter of shaded area = 1/4 perimeter of circle + line AC = ¼ * 3.14 * 2 * 12 + √(12² + 12²) = 18.84 + 12√2 cm = 35.8 cm
Area of Shaded Region = 1/4 area of circle - area of triangle = ¼ * 3.14 * 12² - ½ . 12 * 12
= (¼ * 3.14 - ½) * 12² = 41.04 cm²