A. add a catalyst is the correct answer.
A catalyst never takes part in the reaction, so it does not affect the reaction.
Hope this helps~
PH+pOH=14
4.5+pOH=14
pOH=14-4.5
pOH = 9.5
We know that
[H⁺][OH⁻]=10⁻¹⁴,so
-log([H⁺][OH⁻])=-log10⁻¹⁴
-log [H⁺]+ (- log[OH⁻])= - log10⁻¹⁴,
- log[H⁺] = pH
- log[OH⁻] = pOH
- log10⁻¹⁴=-(-14)log10=14*1=14
pH + pOH =14
Answer:
The answer to your question is: 0.05 M
Explanation:
I'm not sure about the units umol, I think is units mol.
Data
MgF2 = 0.0191 mol
Volume = 400 ml
Molarity = moles / volume
Molarity = 0.0191 / 0.4 l
Molarity = 0.048 ≈ 0.05 M
Answer:
\left \{ {{y=206} \atop {x=82}}Pb \right.
Explanation:
isotopes are various forms of same elements with different atomic number but different mass number.
Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are
- Alpha particle emission \left \{ {{y=4} \atop {x=2}}He \right.
- Beta particle emission \left \{ {{y=0} \atop {x=-1}}e \right.
- gamma radiation \left \{ {{y=0} \atop {x=0}}γ \right.
in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.
Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below
\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right + \left \{ {{y=0} \atop {x=0}}γ\right.
Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right
The group 17 elements of the periodic table have 7 valence electrons and are highly reactive, with low melting and boiling points. The halogens - including fluorine, chlorine and bromine - have a common tendency to form salts, but they are all of a toxic nature.
https://www.google.com/search?q=what+do+all+halogens+have+in+common&rlz=1C5CHFA_enUS710US710&oq=what+do+all+halogens&aqs=chrome.1.69i57j0l5.6043j0j7&sourceid=chrome&ie=UTF-8
