(Rocks Mineral

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

4 years ago

You are given two variables, already declared and assigned values, one of type double, named price, containing the price of an o

Oksi-84 [34.3K]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

//variable to store input

double price;

int totalNumber;

// variable to store total price

double total_price;

cout<<"Enter the price of an order:";

// read the price of an order

cin>>price;

cout<<"Enter the number of orders:";

// read the total number of orders

cin>>totalNumber;

// calculate total price of all orders

total_price=price*totalNumber;

cout<<"total price of all orders: "<<total_price<<endl;

return 0;

}

Explanation:

Declare three variables "price" of double type,"totalNumber" of int type And "total_price" of type double.Read the value of an order and number of orders. The calculate the total price by multiply "price" with "totalNumber" and assign it to variable "total_price". Print the total price.

Output:

Enter the price of an order:12.5

Enter the number of orders:3

total price of all orders: 37.5

7 0

4 years ago

Was LDAP version2 an internet standard in 1998? is it now?

mamaluj [8]

Answer Explanation:

LDAP stand for lightweight directory access protocol 389 is its port number it is an application layer protocol it was first invented in march 1998 and become very popular widespread internet standard in august 1998 its authentication method is very simple the client send user name and password to LDAP server to access this.

4 0

3 years ago

⦁ ¿Cuáles son los recursos naturales que se utilizan en tu comunidad para generar energía eléctrica?

xxTIMURxx [149]

Turbinas de viento y turbinas de agua son utilizadas, entonces la respuesta podria ser viento y agua

7 0

3 years ago

Define a method named swapValues that takes an array of four integers as a parameter, swaps array elements at indices 0 and 1, a

Luba_88 [7]

The program is an illustration of arrays.

Arrays are used to hold multiple values.

The program in java, where comments are used to explain each line is as follows:

import java.util.*;

public class Main{

//This defines the method

public static int[] swapValues(int[] arr) {

//This swaps the first and second array elements

int temp = arr[0];

arr[0] = arr[1]; arr[1] = temp;

//This swaps the third and fourth array elements

temp = arr[2];

arr[2] = arr[3]; arr[3] = temp;

//This returns the swapped array to main

return arr;

}

//The main method begins here

public static void main(String[] args) {

//This creates a Scanner object

Scanner input = new Scanner(System.in);

//This declares an array of 4 elements

int[] intArray = new int[4];

//This gets input for the array

for(int i = 0; i<4;i++){

intArray[i] = input.nextInt();

}

//This calls the swapValues method

intArray=swapValues(intArray);

//This prints the swapped array

for (int i = 0; i < 4; i++){

System.out.print( intArray[i]+ " "); }

}

At the end of the program, the elements are swapped and printed.

Read more about similar programs at:

brainly.com/question/14017034

6 0

3 years ago