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andriy [413]
3 years ago
11

A class has 15 boys and 16 girls. What is the probability that a boy's name is drawn at random?

Mathematics
1 answer:
melomori [17]3 years ago
6 0
15 boys and 16 girls....total is (15 + 16) = 31

probability that a boys name is drawn : boys/total ppl = 15/31
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If the coefficient of determination for a data set is 0.25 and the SSE for the data set is 6, what is the SST for the data set ?
Cerrena [4.2K]

Answer: The SST for the data set is 8.

Step-by-step explanation:

Since we have given that

Coefficient of determination (R²) = 0.25

SSE for the data = 6

SST = ?

As we know the formula for coefficient of determination:

R^2=1-\dfrac{SSE}{SST}\\\\0.25=1-\dfrac{6}{SST}\\\\0.25-1=-\dfrac{6}{SST}\\\\-0.75=-\dfrac{6}{SST}\\\\SST=\dfrac{6}{0.75}\\\\SST=8

Hence, the SST for the data set is 8.

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4 years ago
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Step-by-step explanation:

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Answer:

3

Step-by-step explanation:

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Slope =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{10-[-2]}{3-[-1]}\\\\=\frac{10+2}{3+1}\\\\=\frac{12}{4}\\\\=4

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8 0
3 years ago
What is the lcd of (3x)/(x + 3), 3/(x ^ 2 - 9)
Rudik [331]

Answer:

Simplify the denominator.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

x

2

−

5

x

+

6

Factor

x

2

−

5

x

+

6

using the AC method.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

(

x

−

3

)

(

x

−

2

)

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

(

x

+

3

)

(

x

−

3

)

,

(

x

−

3

)

(

x

−

2

)

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number

1

is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of

1

,

1

is the result of multiplying all prime factors the greatest number of times they occur in either number.

1

The factor for

x

+

3

is

x

+

3

itself.

(

x

+

3

)

=

x

+

3

(

x

+

3

)

occurs

1

time.

The factor for

x

−

3

is

x

−

3

itself.

(

x

−

3

)

=

x

−

3

(

x

−

3

)

occurs

1

time.

The factor for

x

−

2

is

x

−

2

itself.

(

x

−

2

)

=

x

−

2

(

x

−

2

)

occurs

1

time.

The LCM of

x

+

3

,

x

−

3

,

x

−

3

,

x

−

2

is the result of multiplying all factors the greatest number of times they occur in either term.

(

x

+

3

)

(

x

−

3

)

(

x

−

2

)

Step-by-step explanation:

there does that help

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3 years ago
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lozanna [386]

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Step-by-step explanation:

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3 years ago
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